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statuscvo [17]
2 years ago
15

Cos2A + cos2A cot2A = cot2A​

Mathematics
1 answer:
Vlad [161]2 years ago
7 0

cos(2<em>A</em>) + cos(2<em>A</em>) cot(2<em>A</em>) = cot(2<em>A</em>)

cos(2<em>A</em>) + cos(2<em>A</em>) cot(2<em>A</em>) - cot(2<em>A</em>) = 0

cot(2<em>A</em>) sin(2<em>A</em>) + cos(2<em>A</em>) cot(2<em>A</em>) - cot(2<em>A</em>) = 0

cot(2<em>A</em>) (sin(2<em>A</em>) + cos(2<em>A</em>) - 1) = 0

cot(2<em>A</em>) = 0   <u>or</u>   sin(2<em>A</em>) + cos(2<em>A</em>) - 1 = 0

cot(2<em>A</em>) = 0   <u>or</u>   sin(2<em>A</em>) + cos(2<em>A</em>) = 1

cot(2<em>A</em>) = 0   <u>or</u>   sin(2<em>A</em>) cos(<em>π</em>/4) + cos(2<em>A</em>) sin(<em>π</em>/4) = 1/√2

cot(2<em>A</em>) = 0   <u>or</u>   sin(2<em>A</em> + <em>π</em>/4) = 1/√2

[2<em>A</em> = cot⁻¹(0) + <em>nπ</em>]   <u>or</u>

[2<em>A</em> + <em>π</em>/4 = sin⁻¹(1/√2) + 2<em>nπ</em>   <u>or</u>   2<em>A</em> + <em>π</em>/4 = <em>π</em> - sin⁻¹(1/√2) + 2<em>nπ</em>]

(where <em>n</em> is any integer)

[2<em>A</em> = <em>π</em>/2 + <em>nπ</em>]   <u>or</u>

[2<em>A</em> + <em>π</em>/4 = <em>π</em>/4 + 2<em>nπ</em>   <u>or</u>   2<em>A</em> + <em>π</em>/4 = 3<em>π</em>/4 + 2<em>nπ</em>]

[<em>A</em> = <em>π</em>/4 + <em>nπ</em>/2]   <u>or</u>

[2<em>A</em> = 2<em>nπ</em>   <u>or</u>   2<em>A</em> = <em>π</em>/2 + 2<em>nπ</em>]

[<em>A</em> = <em>π</em>/4 + <em>nπ</em>/2]   <u>or</u>

[<em>A</em> = <em>nπ</em>   <u>or</u>   <em>A</em> = <em>π</em>/4 + <em>nπ</em>]

<em>A</em> = (1 + 2<em>n</em>) <em>π</em>/4   <u>or</u>   <em>A</em> = <em>nπ</em>   <u>or</u>   <em>A</em> = <em>π</em>/4 + <em>nπ</em>

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I give you a tricky one Express 108 ×125as a product of prime factors in exponential form
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Answer:

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Step-by-step explanation:

To express the given product (108 X 125) as a product of prime factors

Step 1: Express each of the numbers as a product of its prime factors.

108=2^2 \times 3^3\\125=5^3

Step 2: Write the product together, and combine any like terms if any

Therefore,

108 \times 125=2^2 \times 3^3 \times 5^3

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2 years ago
Please help with this question!!
xxMikexx [17]

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8 0
2 years ago
Two lines have the given equations. Use the LINEAR COMBINATION METHOD to solve.
Maurinko [17]

Using linear combination method, the solution to given system of equations are (-7, -15)

<h3><u>Solution:</u></h3>

Linear combination is the process of adding two algebraic equations so that one of the variables is eliminated

Addition is used when the two equations have terms that are exact opposites, and subtraction is used when the two equations have terms that are the same.

<u><em>Given system of equations are:</em></u>

2x - y = 1  ---- eqn 1

3x - y = -6 ------ eqn 2

Subtract eqn 2 from eqn 1

2x - y = 1

3x - y = -6

(-) -------------

-x = 7

<h3>x = -7</h3>

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<h3>y = -15</h3>

Thus the solution to given system of equations are (-7, -15)

8 0
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