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Solnce55 [7]
2 years ago
7

Help me plz! I dont know how to solve it​

Mathematics
2 answers:
Yuliya22 [10]2 years ago
8 0
The correct answer would be 170%
gizmo_the_mogwai [7]2 years ago
6 0

Answer: 170%

Step-by-step explanation:

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That does not make sense sorry :(
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3 years ago
Help please uh thanks
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12/78 divide both numbers by 6 to simplify
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2 years ago
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A circular plate has circumference 21.4 inches. What is the area of this​ plate? Use 3.14 for pi.
Brut [27]

Answer:

The area of this plate is 36.31\ \text{inches}^2.

Step-by-step explanation:

We have,

Circumference of a circular plate, C = 21.4 inches

The circumference of a circular shape is given by :

C=2\pi r

r is radius of circular shape

r=\dfrac{C}{2\pi}\\\\r=\dfrac{21.4}{2\times 3.14}\\\\r=3.4\ \text{inches}

Area of this plate is given by :

A=\pi r^2\\\\A=\pi (3.4)^2\\\\A=36.31\ \text{inches}^2

So, the area of this plate is 36.31\ \text{inches}^2.

8 0
3 years ago
-1x + 5 = 10 solution please
FinnZ [79.3K]

Answer:i think its -5 because if you subtract 5 from 10 then its five hnd a negative times a negative is a positive

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc
nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

10 word errors.

This means that n = 10

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

6 0
3 years ago
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