Answer:
The answer is add 4.
Step-by-step explanation:
I know this because if you add 4 to 43 that's 47 so that's 1 of the blanks. Add another 4 that's 51. that's another 1. and that's last one is add 4 which makes 54.
Hope this helps.
Answer:
(4,0)
Step-by-step explanation:
we have
----> inequality A
----> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
Verify each ordered pair
case 1) (4,0)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>

----> is true
so
the ordered pair makes both inequalities true
case 2) (1,2)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 3) (0,4)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 4) (2,1)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>

----> is not true
so
the ordered pair not makes both inequalities true
That means that the first rectangle and the first triangle ave athe same perimiter
so therefor
perimiter=sides added up
rectangle has 4 sides bu 2 is given so double it since the other side is same legnth
rec=x+x+4
multiply 2
2x+2x+8=4x+8=perimiter
this is equal to perimiter of triangle which is
x+9+x+5+x=3x+14
therefor
4x+8=3x+14
subtract 3x from both sides
x+8=14
subtract 8 from both sides
x=6
first one x=6
second rectangle and second triangle
s+7 and 3s
2 sides
2s+14+6s=p
8s+14=p
traignel=2s+12+2s+12+2s+12=6s+36=p
they are equal so
8s+14=6s+36
subtract 6s from both sides
2s+14=36
subtract 14 from both sides
2s=22
divide both sideds by 2
s=11
the values are
pair one:
x=6
pair 2:
s=11
Answer:
14
Step-by-step explanation:
Arithmetic expressions are best evaluated using a reliable calculator. The Google calculator always follows the Order of Operations, so can give you a good answer to such questions.
(1/4)^-2 - (5^0)(2)(1^-1)
= 16 - (1)(2)(1) . . . . evaluate the exponents first
= 16 -2 . . . . . . . . . evaluate the product next
= 14 . . . . . . . . . . . finally, evaluate the sum
___
The rule of exponents is ...
a^-b = 1/(a^b)