5. Emma, Brandy, and Damian will cut a rope that is 29.8 feet long into

Kruka [31]

Answer:

Firstly, from the diagram we are given that the length of XB is congruent to BZ, and YC is congruent to CZ. Based on this information, we know that B is the midpoint of XZ, and C is the midpoint of YZ. This means that BC connects the midpoints of segments XZ and YZ. Now that we know this, we can use the Triangle Midsegment Theorem to calculate the length of BC. This theorem states that if a segment connects the midpoints of two sides of a triangle, then the segment is equal to one-half the length of the third side. In this scenario, the third side would be XY, which has a length of 12 units. Therefore, the length of BC = 1/2(XY), and we can substitute the value of XY and solve this equation:

BC = 1/2(XY)

BC = 1/2(12)

BC = 6

Step-by-step explanation:

Please support my answer.

6 0

2 years ago

If f(x) = 2^x + 4 and g(x) = x^2 – 4 what is the value of f(5) +g(-3)

Anon25 [30]

f(5)=2^5+4

f(5)=32+4=36

g(-3)=(-3)^2-4

=9-4

=5

f(5)+g(-3)=36+5

=41

8 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

professor190 [17]

Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0

3 years ago

What is the sum1,000+2,000=

Valentin [98]

Answer:

3000

Step-by-step explanation:

1000 + 2000 = 3000

4 0

3 years ago

Help me me me me plz thx if you do

prohojiy [21]

Answer:

75% left is not taken up so do the Ab to the other

Step-by-step explanation:

0.75 sorry if Im wrong

6 0

3 years ago