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2 years ago

The given angle is in standard position. Determine the quadrant in which the angle lies. -25°

Mathematics

2 answers:

Veronika [31]2 years ago

6 0

The terminal end of the angle has dropped 25° under the x-axis.
That's Quadrant-IV .

AURORKA [14]2 years ago

3 0

The answer is C. quadrant IV

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Three students are from a plate of cookies.Daniel ate 1/12 of the cookies, Mariel ate 4/12 of the cookies, and Tamika ate 2/12 o

Mrac [35]

Answer:

5/12 of cookies left on the plate

Step-by-step explanation:

we have to add to know what part of the dish ate and then subtract it from the total

1/12 + 4/12 + 2/12 =

when we are adding fractions with the same denominator we simply add the above

1 + 4 + 2 = 7

1/12 + 4/12 + 2/12 = 7/12

now to the total of the plate that would be 1 we subtract what they ate

1 - 7/12 =

the whole 1 can be expressed as 12/12 since if we do the 12/12 = 1 account

12/12 - 7/12

for the subtraction with the same denominator the same thing happens as for the sum, we only do it with the top

12 - 7 = 5

12/12 - 7/12 = 5/12

8 0

3 years ago

Read 2 more answers

Words to know

Volgvan

Answer: Switch a with c and you are good. I think that is what you are asking?

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the volume of the solid.

Romashka-Z-Leto [24]

90 cu in.
V= L * W * H
Split shape into two figures

3 0

1 year ago

A line includes the points (1, 6) and (10, 4). What is its equation in point-slope form? Use one of the specified points in your

Kaylis [27]

Y2-y1/x2-x1
4-6/10-1
-2/9 is the slope

y-y1=m(x-x1)
y-6=-2/9(x-1)
y-6=-2/9x-2/9
Multiply both sides by 9
9y-54=-2x-2
2x+9y=52

Therefore 2x+9y=52 is the equation

6 0

2 years ago

(b) how many measurements must be averaged to get a margin of error of ±0.0001 with 98% confidence? (round your answer up to the

goblinko [34]

Given that the scale readings of the laboratory scale is normally distributed with an unknown mean and a standard deviation of 0.0002 grams.

Part A:

If the weight is weighted 5 times and the mean weight is 10.0023 grams, the 98% confidence interval for μ, the true mean of the scale readings is given by:

$98\% \ C. \ I.=\bar{x}\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right) \\ \\ =10.0023\pm2.33\left(\frac{0.0002}{\sqrt{5}}\right) \\ \\ =10.0023\pm2.33(0.000089) \\ \\ =10.0023\pm0.00021 \\ \\ =(10.0023-0.00021, \ 10.0023+0.00021) \\ \\ =(10.0021, \ 10.0025)$

Thus, we are 98% confidence that the true mean of the scale readings is between 10.0021 and 10.0025.

Part B:

To get a margin of error of +/- 0.0001 with a 98% confidence, then

$\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right)=\pm0.0001 \\ \\ \Rightarrow2.33\left(\frac{0.0002}{\sqrt{n}}\right)=0.0001 \\ \\ \Rightarrow\left(\frac{0.0002}{\sqrt{n}}\right)= \frac{0.0001}{2.33} =0.0000429 \\ \\ \Rightarrow\sqrt{n}= \frac{0.0002}{0.0000429} =4.66 \\ \\ \Rightarrow n=4.66^2=21.7156\approx22$

Therefore, the number of <span>measurements that must be averaged to get a margin of error of ±0.0001 with 98% confidence is 22.</span>

8 0

3 years ago