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aleksandr82 [10.1K]
3 years ago
12

The given angle is in standard position. Determine the quadrant in which the angle lies. -25°

Mathematics
2 answers:
Veronika [31]3 years ago
6 0
The terminal end of the angle has dropped 25° under the x-axis.
That's Quadrant-IV .
AURORKA [14]3 years ago
3 0
The answer is C. quadrant IV
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. Anne is pushing a wheelbarrow filled with mulch to place in her garden. She is pushing the wheelbarrow with a force of 70 N at
Kruka [31]

<u>Answer:</u>

When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules

<u>Solution:</u>

We know \text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})\times\text { Distance (D) }

Anne is pushing the wheelbarrow with a force of 70 N at an angle of 50^{\circ} with the horizontal

So the force of Anne will be F=70 \cos 50^{\circ}=(70 \times 0.64)=44.8 \mathrm{N}

She pushes the wheelbarrow 25 meter, So D = 25 meters

So, the work,F\times D=(44.8 \times 25)=1120 \text { Joules }

Anne has done total 1120 joules work.

4 0
3 years ago
What’s the answer to this one! 15 points!
Phoenix [80]

Answer:

D

Step-by-step explanation:

Because they are opposite of each other

5 0
3 years ago
Read 2 more answers
Which description is correct for the polynomial 2x² + 2?
Blizzard [7]

Answer:

The polynomial is a quadratic binomial

Step-by-step explanation:

we have

2x^{2}+2

Classify the polynomial

<u>By the number of terms</u>

we know that

A polynomial with two terms is a binomial

<u>By the Degree of a Polynomial</u>

we know that

The degree of a polynomial is calculated by finding the largest exponent in the polynomial

In the given problem the largest exponent is 2

so

Is a quadratic equation

therefore

The polynomial is a quadratic binomial


6 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE, THANKS! :)
marissa [1.9K]

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

5 0
3 years ago
Can someone help me find the answer and find out how to get the answer for X, Y, T, W, and Z
alexandr1967 [171]

would it be 90 ? because of the big angle

7 0
4 years ago
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