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dolphi86 [110]
3 years ago
11

Two cars leave towns 340 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hou

r more than the other's. If they meet in 2 hours, what is the rate of the slower car?
Mathematics
1 answer:
Nana76 [90]3 years ago
6 0

Answer:

  78 km/h

Step-by-step explanation:

Let s represent the speed of the slower car. The total speed of the two cars is their closing speed:

  (s) + (s+14 km/h) = (340 km)/(2 h)

  2s + 14 km/h = 170 km/h . . . . . simplify

  s + 7 km/h = 85 km/h . . . . . . . . divide by 2

  s = 78 km/h . . . . . . . . . . . . . . . . subtract 7 km/h

The rate of the slower car is 78 km/h.

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-100 feets, means elevation of Jacksonville city is below sea level (elevation points less than 0, are below sea level).

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Step-by-step explanation:

Q3

(a) If 0 < |x − 1| < δ, then |f(x) − 2| < 2

What this means is, how far can x stray from the x=1 line such that f(x) stays within 2 units of the y=2 line (0 < f(x) < 4).

If we move 2 units left of x=1, we get f(x) = 4.

If we move about 3.5 units right of x=1, we get f(x) = 4.

Therefore, δ can't be more than 2.

(b) If 0 < |x| < δ, then |f(x) − 3| < 1

What this means is, how far can x stray from the x=0 line such that f(x) stays within 1 unit of the y=3 line (2 < f(x) < 4).

If we move 1 unit left of x=0, we get f(x) = 4.

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Therefore, δ can't be more than 1.

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(b) No.  f(1) = 300, so even if δ = 0, f(x) will be less than 400.

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