Answer:
![y=\frac{1}{6} (x+5)^2-4.5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B6%7D%20%28x%2B5%29%5E2-4.5)
![y=\frac{-1}{20} (x-10)^2+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-1%7D%7B20%7D%20%28x-10%29%5E2%2B1)
Step-by-step explanation:
focus at (-5, -3), and directrix y = -6
Directrix y=-6 so its a vertical parabola
so equation is
(x-h)^2 = 4p(y-k)
(h,k) is the center
P is the distance between focus and vertex
distance between focus and directrix = 2p
distance between -3 and y=-6 is 3
2p = 3
p = 3/2 or p = 1.5
Focus is (h, k+p)
given focus is (-5, -3) so h= -5 and k+p = -3
k+p=-3, plug in 1.5 for p
k + 1.5 = -3
subtract 1.5 on both sides
k = -4.5
(x-h)^2 = 4p(y-k)
![(x+5)^2= 4(1.5) (y+4.5)](https://tex.z-dn.net/?f=%28x%2B5%29%5E2%3D%204%281.5%29%20%28y%2B4.5%29)
![(x+5)^2= 6(y+4.5)](https://tex.z-dn.net/?f=%28x%2B5%29%5E2%3D%206%28y%2B4.5%29)
divide by 6 on both sides
then subtract 4.5 on both sides
![y=\frac{1}{6} (x+5)^2-4.5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B6%7D%20%28x%2B5%29%5E2-4.5)
focus at (10, -4), and directrix y = 6.
Directrix y=6 so its a vertical parabola
so equation is
(x-h)^2 = 4p(y-k)
distance between focus and directrix = 2p
distance between -4 and y=6 is -4-6=-10
2p = -10
p = -5
Focus is (h, k+p)
given focus is (10, -4) so h= 10 and k+p = -4
k+p=-4, plug in 5 for p
k - 5 = -4
add 5 on both sides
k = 1
(x-h)^2 = 4p(y-k)
![(x-10)^2= 4(-5) (y-1)](https://tex.z-dn.net/?f=%28x-10%29%5E2%3D%204%28-5%29%20%28y-1%29)
![(x-10)^2= -20(y-1)](https://tex.z-dn.net/?f=%28x-10%29%5E2%3D%20-20%28y-1%29)
divide by -20 on both sides and add 1 on both sides
![y=\frac{-1}{20} (x-10)^2+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-1%7D%7B20%7D%20%28x-10%29%5E2%2B1)