The price of a staff ticket and the price of a student ticket is $8 and $14
Given:
Day 1:
Number of staff tickets sold = 3
Number of students tickets sold = 1
Total revenue day 1 = $38
Day 2:
<em>Number of staff tickets sold</em> = 3
<em>Number of students tickets sold</em> = 2
<em>Total revenue day</em> 2 = $52
let
<em>cost of staff tickets</em> = x
<em>cost of students tickets</em> = y
The equation:
<em>3x + y = 38 (1)</em>
<em>3x + y = 38 (1)3x + 2y = 52 (2)</em>
subtract (1) from (2)
2y - y = 52 - 38
y = 14
substitute y = 14 into (1)
3x + y = 38 (1)
3x + 14 = 38
3x = 38 - 14
3x = 24
x = 24/3
x = 8
Therefore,
cost of staff tickets = x
= $8
cost of students tickets = y
= $14
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f(n) = f(n+1) +3
f(1) = f(2) +3
f(2) =f(3) +3
f(3) = f(4) +3
So f(1) = f(n) + 3* (n-1)
Put n=4 here so you found
f(1) = f(4) + 3* 3
= 22 +9
=31 ans
hope it helps
Answer:
- 3 < p < 4
Step-by-step explanation:
Given p is greater than - 3 then - 3 is less than p
- 3 < p < 4
Answer:
y can be any real number
Step-by-step explanation:
8(y + 7) > 8y + 3
Distribute
8y+56 > 8y+3
Subtract 8y from each side
8y-8y +56 > 8y-8y +3
56 > 3
This is always true so the inequality is always true
y can be any real number
