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Firlakuza [10]
3 years ago
15

Ayo can someone help me with this

Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0
Answer:
1.25 x 3 = $3.75
Vlad [161]3 years ago
5 0

Answer:

$3.75

Step-by-step explanation:

each minute is 25 cents

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# 6
zhuklara [117]

9514 1404 393

Answer:

  y = 5x - 7

Step-by-step explanation:

We can make an equation for the perpendicular line by swapping the x- and y-coefficients, negating one of them. Then we can use that form with the given point to see what the constant is.

  10x -2y = ...

Removing a common factor of 2 gives ...

  5x -y = 5(2) -(3) = 7 . . . .  using (x, y) = (2, 3), we can find the constant

Solving for y, we get ...

  5x -7 = y . . . add y-7

  y = 5x -7 . . . write in the desired form

5 0
3 years ago
Which number makes the following number sentence true 3+6=6+
3241004551 [841]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
6 5/6 - 3 1/3 Simplified
Furkat [3]
6 - 3 = 3
5/6 - 1/3 = 5/6 - 2/6 = 3/6 = 1/2

answer is : 3 1/2 ( or 7/2)
7 0
3 years ago
A retired auto mechanic hopes to open a rustproofing shop. Customers would be local new-car dealers. Two locations are being con
const2013 [10]

It is convenient to let a spreadsheet or graphing calculator do the math for this. Functions can be defined for cost and profit, and evaluated at each of the volumes of interest.

a1) For 200 cars, the Outside location yields the greatest profit

a2) For 300 cars, the City location yields the greatest profit

b) The sites yield the same profit for a volume of 278 cars.

3 0
3 years ago
Which of the following points would be a solution to this system of linear inequalities? ​
pychu [463]

Let's plug in both x and y values in the equation and check if the inequality is true...

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

(4,1) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 4 and y as 1

1 \leqslant 4 + 1 \\ 1 <  -  \frac{4}{2}  - 1

0  \leqslant  4 + 1 \\ 1 <  - 2 - 1

0 \leqslant 5 \\ 1 <  - 3

  • <em>This is not a solution because both are not true, Only one equation is giving true as answer which is not correct!~</em>

\purple{ \rule{300pt}{3pt}}

(0, - 3) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 0 and y as -3

- 3 \leqslant 0 + 1 \\  - 3 <  -  \frac{0}{2}  - 1

- 3 \leqslant 1 \\  - 3 <  - 0 - 1

- 3 \leqslant 1 \\  - 3 <  - 1

  • <em>This is a solution because both are true, </em><em>Both the </em><em>equations</em><em> </em><em>are</em><em> </em><em>true</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>ordered</em><em> </em><em>pair</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>solution</em><em>!</em><em>~</em>

<u>Thus</u><u>,</u><u> </u><u>Option</u><u> </u><u>B</u><u> </u><u>(</u><u>0</u><u>,</u><u>-</u><u>3</u><u>)</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>correct</u><u> </u><u>choice</u><u>.</u><u>.</u><u>.</u><u>.</u>

6 0
3 years ago
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