Answer:
Perimeter of i - 22CM
Area of i - 13CM^2
Perimeter of ii -38CM
Area of ii -66CM^2
Perimeter of iii -30CM
Area of iii- 42CM^2
Perimeter of iv - 50CM
Area of iv- 126CM^2
Step-by-step explanation:
SHAPE I:
PERIMETER = S + S + S + S + S +S
= 7 + 1 + 5 +3 +4 +2
= 22CM
AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2
Total = 8 + 5 = 13cm^2
SHAPE II:
PERIMETER = S + S + S + S + S +S
= 4 + 4 +5 + 6 + 9 + 10
= 38 CM
AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2
Total = 50+16 =66 cm^2
SHAPE III:
PERIMETER = S + S + S + S + S +S
= 9 + 2 + 3 + 4 + 6 + 6
= 30CM
AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2
Total = 36 + 6 =42 cm^2
SHAPE IV:
PERIMETER = S + S + S + S + S +S
= 9 + 10 + 4 + 6 + 6 + 15
= 50 CM
AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2
Total = 90 + 36 = 126cm^2
HOPE THIS HELPED
Answer:
anything raised to the power of zero= 1
(1+1/4^½)²
(1 + 1/2)²
(3/2)²
9/4
=2.25
when you simplify 2/4 it equals 1/2. Making them both equal the same.
2/3 when you double the numbers to make a bigger fraction you make 4/6.
2x2 = 4/ 3x3= /6 = 4/6
3/9 simplified is 1/3. Three goes into three one time, making the top one and three goes into 9 three times making the bottom 3.
When 9/12 is rounded down it is equivalent to 3/4
Solve for x:
x^2 + 10 x + 12 = 36
36 = 36:
x^2 + 10 x + 12 = 36
Subtract 12 from both sides:
x^2 + 10 x = 24
Add 25 to both sides:
x^2 + 10 x + 25 = 49
Write the left hand side as a square:
(x + 5)^2 = 49
Take the square root of both sides:
x + 5 = 7 or x + 5 = -7
Subtract 5 from both sides:
x = 2 or x + 5 = -7
Subtract 5 from both sides:
Answer: x = 2 or x = -12 Thus the Answer is A.
Answer:
Solution given:
Cos X=Adjacent/hypotenuse
Cos X=6.5/8.4
x=Cos-¹(6.5/8.4)
<u>x=39.3</u>°
