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Lerok [7]
3 years ago
6

First, read in an input value for variable valCount. Then, read valCount integers from input and output each integer on a newlin

e followed by the string" reports.".
Ex: If the input is 3 70 65 75, the output is:

70 reports.
65 reports.
75 reports.​
Computers and Technology
1 answer:
ratelena [41]3 years ago
4 0

Answer:

The program in Python is as follows:

valCount = int(input())

reports = []

for i in range(valCount):

   num = int(input())

   reports.append(num)

   

for i in reports:

   print(i,"reports.")

Explanation:

This gets input for valCount

valCount = int(input())

This creates an empty list

reports = []

This gets valCount integer from the user

<em>for i in range(valCount):</em>

<em>    num = int(input())</em>

<em>Each input is appended to the report list</em>

<em>    reports.append(num)</em>

This iterates through the report list

for i in reports:

This prints each element of the report list followed by "reports."

   print(i,"reports.")

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Compared to using a command line, an advantage to using an operating system that employs a gui is ________.
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Convert infix to postfix
kvv77 [185]

Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

 

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

 

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

 

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;    

else

operators.pop();

}

else

{

while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

operands.push(operators.pop());

operators.push(c);

}

}

while (!operators.isEmpty())

operands.push(operators.pop());

while (!operands.isEmpty())

calculation+=operands.pop();

calculation=calculation.reverse();

return calculation;

}

Explanation:

  • Create the checkSymbol function to see what symbol is being passed to the stack.
  • Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
  • Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
  • While the operators is  not empty, keep pushing the character to the operators stack.
  • At last reverse and return the calculation which has all the results.
4 0
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