Answer:
Number of strings = (10, 2)×(8,3) = 2520
Explanation:
The number of possible combinations for taking two 0's is C(10, 2)
It remains 8 Positions
The number of possible combinations for taking three 1's is C(8,3)
So there remains 5 spots
Um whichever is better for you! ummm whats the point of this question?
VRAM because VRAM is used for graphic intensive workloads
I think it should be in the design tab