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motikmotik
3 years ago
7

What is the slope of any line parallel to the line 8x+9y=3 in standard (x,y) coordinate plane?

Mathematics
1 answer:
Natalka [10]3 years ago
5 0
8x + 9y = 3
9y = -8x + 3
y = -8/9x + 1/3...the slope here is -8/9. A parallel line will have the same slope....so any line parallel to 8x + 9y = 3 will have a slope of -8/9
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Can someone help me for this question please? Why I got wrong answer. ASAP!!!
Snowcat [4.5K]

Answer:

a=8.06

A=29.74

B=60.26

Step-by-step explanation:

This is a right angled triangle and Pythagoras theorem is to be obeyed.

To get c, we follow the Pythagoras rule that says

Hyp² = Opp² + Adj²

c= Hypotenuse

c²= a² + b²

c² = 4² + 7²

c² = 65

c = √65 = 8.06

For angle A,

the opposing side to the angle = a = 4

The adjacent side to the angle = b = 7

Following trigonometry rule.

Tan A = opp/adj

Tan A = 4/7

A = Tan–¹(4/7)

A = 29.74°

For angle B,

Opposing side = 7

Adjacent side = 4

Tan B = 7/4

B = Tan-¹(7/4)

B = 60.26°

5 0
3 years ago
the relationship between money earned and hours worked is linear. joe computes the slope between (4, 30) and (12, 90), then comp
julia-pushkina [17]
Slope = rise/run =[y2-y1]/[x2-x1]

1) slope = [90 - 30] / [12 - 4] = 60 / 8 = 15/2

2) slope = [75 - 30] / [10 - 4] = 45 / 6 = 15 / 2

The slopps are equal.
6 0
3 years ago
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elena55 [62]
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8 0
2 years ago
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find the volume of cubical box . if the cost of painting of outer surface is rs 1440 at the rate rs 15 per mcube
bearhunter [10]
Surface of a cubical box=6(side²)

1)We have to calculate the surface of this cubical box.
Rate=cost of painting / surface  ⇒surface=cost of painting/rate

Data:
Rate=$15/m²
cost of painting=$1440

Surface=$1440/($15/m²)=96 m²

2)We find out the length of the side:

Surface of a cubical box=6(side²)

Data:
Surface of a cubical box=96 m2

Therefore:
96m²=6 (side²)
side²=96 m²/6
side²=16 m²
side=√(16 m²)=4 m

3) We find the volume of a cubical box.
volume=(side³)
volume=(4 m)³
volume=64 m³

Answer: the volume of this cubical box would be 64 m³.

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3 years ago
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