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3 years ago

Write each repeating decimal using bar

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

*The bar is supposed to go on top of the number, but I will put it at the bottom because I don't know how to do it at the top*

a) 0.5

b) 0.13456

Step-by-step explanation:

a) The 5 is repeating so you put the bar on top of the 5

b) The number 13456 is repeated so you put the bar on top of the 13456

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At Cindy's birthday each guest will get one-third of a medium sized pizza. There will be 12 people at the party, including Cindy

tiny-mole [99]

Answer: 4 pizzas

Step-by-step explanation:

There are to be 12 people at the party.

Each person is expected to take 1/3 of a pizza.

The total number of pizza needed is therefore:

= No. of people * quantity of pizza

= 12 * 1/3

= 4 pizzas

Note: Answer would be 6 if each guest wanted 1/2 of a pizza.

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2 years ago

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Step-by-step explanation:

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3 years ago

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The value of 33 + 42 = ___.

frez [133]

Answer:

Step-by-step explanation:

We line up the tens place of 33 and 42 as well as the ones place so that it looks like:

+42

--------

Then we add first the ones, which is 3 + 2 for 5. Then we add the tens together, 3 + 4 is 7. We put the five first since its in the ones place and the 7 second since its in the tens place for 75.

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2 years ago

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The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: