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3 years ago

F divided by 28 equal 24

Mathematics

2 answers:

BabaBlast [244]3 years ago

6 0

You can translate to:

F ÷ 28 = 24

F/28 = 24 Cross Multiply

F = 28 * 24

F = 672

SVEN [57.7K]3 years ago

5 0

First you F divided by 28 is 24
you carry 24 to the other side which will be 28 multiplied by 24= 672
672 divided by 24 is 28
672 divided by 28 is 24
The answer is 672

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Solve the system of linear equations using either substitution or the elimination method.

lara31 [8.8K]

Answer:

x = -1

y = 2

Step-by-step explanation:

x + y = 1

y = -x + 1

y = -x + 1 (Multiply this by -1)

y = 3x +5

-y = x - 1

y = 3x +5

0 = 4x + 4

4x = -4

x = -1

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-1 + y = 1

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4 0

3 years ago

(3^2+4−2)(2^2−3−4) can you guys please solve this for me please.

Degger [83]

Answer:

-33

Step-by-step explanation:

$(3^2+4-2)(2^2-3-4)$

$(9+4-2)(4-3-4)$

$(13-2)(1-4)$

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3 years ago

A roll of fabric was 120 inches long. A customer bought 2 feet of the fabric.

MAVERICK [17]

the correct answer is OB. 7.

7 0

3 years ago

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Assuming the amount of money college students spend on text books each semester is symmetrical with a mean of 500 and a standard

TiliK225 [7]

16% percent of the students paid MORE than Jane.

The mean(μ) of money spent on textbooks is 500

The standard deviation(σ) of money spent on textbooks is 50

Money paid by Jane for her books is $550

We will use this formula,

Ζ=x-μ/σ

To find: the percentage of students paid MORE than Jane for the textbooks

$P(X > 550)$ =?

Solution:

$P(X > 550)=1-P(X$ ≤ $550)$

= $1-P($ Ζ≤ $\frac{550-500}{50} )$

=1-P(Ζ≤ 1)

=1-0.8413

=0.1587

≈16%

Therefore, 16% percent (approx) of the students paid MORE than Jane.

Learn more about mean and standard deviation here brainly.com/question/4388715

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3 0

2 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers