Let
A=8t-3
B=6t+5
we know that
<span>total earnings=A+B
</span>so
total earnings=(8t-3)+(6t+5)------> (8t+6t)+(-3+5)------> (14t+2) <span>dollars
the answer is
</span>(14t+2) dollars<span>
</span>
Hello,
multiple of 9 betheen 50 and 99 are :54,63,72,81,99
and 54,72 are even.
5-4=1 and not 5
7-2=5 ok
72 is the number searched.
Answer:
There are 1% probability that the last person gets to sit in their assigned seat
Step-by-step explanation:
The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.
If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.
LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!
Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.
P = 99!/100! = 99!/ (100 * 99!) = 1/100
There are 1% probability that the last person gets to sit in their assigned seat
The answer is 1/5, or 0.2, because if you're always putting the slip back in, then there will always by 5 slips to choose from, therefore making the probability 1 out of 5. I hope this helps!
36 divided by 3 plus 90 divided by 3 I think I hope this helps u
