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2 years ago

Formula for triangle are

Mathematics

1 answer:

Greeley [361]2 years ago

6 0

The formula for a triangle:

Base times height divided by 2

Equation Form:

b×h÷2

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Someone please help! I’ll give brainliest!!

anyanavicka [17]

Answer:

The answer is 65.97 yd^3

Step-by-step explanation:

The volume of a cone is: v = $\pi r^{2}\frac{h}{3}$

So, v = $\pi$ (3^2)(7/3) = 65.97345 yd^3

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2 years ago

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$

Therefore, the equivalent expression after expanding is given as:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

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2 years ago

Quiz

Serjik [45]

Answer:

Step-by-step explanation:

5^2 = 25 5^3 = 125 them two added together equals 150

6^2 = 36 so 36 plus 36 equals 72

150-72=78

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2 years ago

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At a fair, each person can spin two wheels of chance. The fist wheel has numbers 1,2, and 3. The second wheel has the letters A

AlexFokin [52]

The answer to Part (B) is 4/6

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2 years ago

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What is a common factor for the two fractional terms StartFraction 5 over 8 EndFraction x andStartFraction 11 over 8 EndFraction

Dafna1 [17]

Answer:

$\frac{1}{8x}$

Step-by-step explanation:

Given two fractional terms $\frac{5}{8x}\ and\ \frac{11}{8xy}$ . Their common factor is a value or function that can go in both fractional terms. The terms can be written as shown.

$\frac{5}{8x} = 5 *\frac{1}{8x}$

$\frac{11}{8xy} = 11 * \frac{1}{8x} * \frac{1}{y}$

It can be seen from the both equations that they both have $\frac{1}{8x}$ as one of their factors i.e <em>1/8x is common to both fractional terms</em>. This gives the common factor for the two fractional terms as $\frac{1}{8x}$

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2 years ago

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