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3 years ago

Is there a dilation the Maps shape lll onto shape ll if so what is the scale factor and is it in enlargement or reduction?

Mathematics

1 answer:

DochEvi [55]3 years ago

6 0

Answer:

steps below

Step-by-step explanation:

Vertex of Shape I : (1,1) (2,1) (2,2) (1,2) ---- (x,y)

Vertex of Shape II : (3,3) (6,3) (6,6) (3,6) ---(x',y') : (x*3 , y*3)

Vertex of Shape III : (2,2) (4,2) (4,4) (2,4) --- (x'',y'') -> (x' , y') : (x''*1.5 , y''*1.5)

Shape I dilate on to Shape II: Enlargement with scale factor of 3

dilation the Maps shape lll onto shape ll : Enlargement with scale factor of 1.5

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Most college-bound students take either the SAT(Scholastic Assessment Test) or the ACT (which originally stood for American coll

Jlenok [28]

Answer:

Luis would need to have a SAT score of 574.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Nicole's z-score:

ACT scores have a mean of about 21 with a standard deviation of about 5, which means that $\mu = 21, \sigma = 5$

Nicole gets a score of 24, which means that $X = 24$ . Her z-score is:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{24 - 21}{5}$

$Z = 0.6$

What score would Luis have to have on the SAT to have the same standardized score(z-score) as Nicole's standardized score on the ACT?

Luis would have to get a score with a z-score of 0.6, that is, X when Z = 0.6.

SAT scores have a mean of about 508 with a standard deviation of about 110, which means that $\mu = 508, \sigma = 110$ .

The score is:

$Z = \frac{X - \mu}{\sigma}$

$0.6 = \frac{X - 508}{110}$

$X - 508 = 0.6*110$

$X = 574$

Luis would need to have a SAT score of 574.

8 0

2 years ago

The student council sold jars of mixed nuts at their bazaar they were given 40 empty jars. They paid $19.60 for the nuts and $11

Alex Ar [27]

Answer:

$\$1.75$

Step-by-step explanation:

Total amount paid for the nuts is $19.60

Total amount paid for the ribbons is $11.20

Profit made on each jar is 98￠= $0.98

Cost price of the nuts and ribbon for the 40 jars is $19.6+11.2=\$30.8$

Cost price for nuts and ribbonn for one jar = $\dfrac{30.8}{40}=\$0.77$

Selling price is the sum of the cost price and profit.

Selling price for one jar = $0.77+0.98=\$1.75$

They charged $\$1.75$ for each jar.

3 0

2 years ago

After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos

igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

$d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}$