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laila [671]
3 years ago
7

Is there a dilation the Maps shape lll onto shape ll if so what is the scale factor and is it in enlargement or reduction?

Mathematics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

steps below

Step-by-step explanation:

Vertex of Shape I : (1,1) (2,1) (2,2) (1,2)   ---- (x,y)

Vertex of Shape II : (3,3) (6,3) (6,6) (3,6)   ---(x',y') : (x*3 , y*3)

Vertex of Shape III : (2,2) (4,2) (4,4) (2,4)  --- (x'',y'') -> (x' , y') : (x''*1.5 , y''*1.5)

Shape I dilate on to Shape II: Enlargement with scale factor of 3

dilation the Maps shape lll onto shape ll : Enlargement with scale factor of 1.5

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Compare the graph of m(x) = 0.7x² + 4 with the graph of n(x) = x².
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Answer:

B.) The graph of m(x) is wider.

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Step-by-step explanation:

When the coefficient before x² is greater than 1, the curve of the graph is narrower. When the coefficient is less than 1, the curve of the graph is wider.

When the coefficient in front of x² is positive, the graph opens upwards. When the coefficient is negative, the graph opens downwards.

The axis of symmetry is the "x" value which divides the curve into two equal sections. Their axis of symmetry are both x = 0 because their vertexes (the lowest point of the curve) are both at x = 0.

The vertex can be found by plugging x = 0 into both of the equations and then solving. The resulting value is the "y" position of the vertex.

m(0) = 0.7(0)² + 4                        n(0) = (0)²

m(0) = 0 + 4                                 n(0) = 0

m(0) = 4

Therefore, the vertexes are m(x) =  (0,4) and n(x) = (0,0).

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