Answer:
5 nickles in a quator.
Step-by-step explanation:
The two numbers could be 8 and 9.
8×8=64 and 9×9=81.
81-64=17.
Answer:
area of sector BCD =60/360×π×10²=52.36ft²
a area of sector ADC =90/360×π×√50²=39.27ft²
actual <u>area</u><u> </u><u>=</u><u>5</u><u>2</u><u>.</u><u>3</u><u>6</u><u>ft²-39</u><u>.</u><u>2</u><u>7</u><u>f</u><u>t</u><u>²</u><u>=</u><u>1</u><u>3</u><u>.</u><u>0</u><u>9</u><u>=</u><u>1</u><u>3</u><u>ft²</u>
I'm assuming it is asking for surface area.
SA = 2(lw) + 2(hw) + 2(lh)
SA = 2(3*4) + 2(4*8) + 2(3*8)
SA = 2(12) + 2(32) + 2(24)
SA = 24 + 64 + 48
SA = 136 square feet
6/9
8/12
10/15
12/18
etc
etc
etc