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3 years ago

In which quadrant is ? located if cos? is positive and cot? is negative?

Mathematics

1 answer:

Elodia [21]3 years ago

7 0

Hello :
if cos? is positive and cot? is negative? in 4 <span>quadrant</span>

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0.3(3a-4)-0.05(8a)(-7a)

Anit [1.1K]

Answer:

2.8a²+0.9a - 1.2

Step-by-step explanation:

Given the expression 0.3(3a-4)-0.05(8a)(-7a)

Expand using the distributive law

0.3(3a-4)-0.05(8a)(-7a)

0.3(3a)-0.3(4)-0.05(8a)(-7a)

0.9a-1.2 - 0.05(8a)(-7a)

0.9a - 1.2 + 2.8a²

Rearrange

2.8a²+0.9a - 1.2

Hence the required expression is 2.8a²+0.9a - 1.2

3 0

2 years ago

The endpoints of PQ are (4,1) and Q(4,8)

tatuchka [14]

Answer:

Search this up on google to find out what the answer is because no one is going to know how to do it.

5 0

3 years ago

A 12-sided sold has faces numbered 1 to 12. The table shows the results of rolling the solid 200

Alik [6]

Answer:

4/25 maybe?

Step-by-step explanation:

7 0

2 years ago

Find the sum of a finite geometric sequence from n=1 to n=8, using the expression -2(3)^n-1

MissTica

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}
\end{cases}
\\\\\\
\sum\limits_{n=1}^{8}~-2(3)^{n-1}~~
\begin{cases}
n=8\\
a_1=-2\\
r=3
\end{cases}\implies S_8=-2\left( \cfrac{1-3^8}{1-3} \right)
\\\\\\
S_8=\underline{-2}\left( \cfrac{1-6561}{\underline{-2}} \right)\implies s_8=1-6561\implies S_8=-6560$

8 0

3 years ago

I would appreciate if someone could answer this question I will give a brainlist for whoever explains and answers ;)

AleksandrR [38]

Answer:

Since this is a right triangle with one angle and hypotenuse given and opposite side unknown, we can use the definition of sine to find the unknown side.

sin 17 = x/hypotenuse = x/19

x = 19sin17 = 5.6

4 0

2 years ago