We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.
The answer is 0.1492.
First term: -9
Common difference: 7
a(n) = -9 + 7(n-1), for n = {1, 2, 3, ... }
Check: what is the first term? let n=1. Then a(1) = -9 + 7(1-1) = -9.
This is correct.
Substitute the value of the variable into the expression and simplify, its theta arrow-to-the-right, pi/4 times 1-tan theta/sin theta - cos theta (i cant type the signs on computer, sorry
Answer:
50 boys
Step-by-step explanation:
2/4 = 1/2
25*2=50
