Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Using the figure below find what m<_7 equals. (show work if possible)

miss Akunina [59]

Answer:

68

Step-by-step explanation:

m7 + m8 = Straight line = 180

So, m7 = 180 - 112 = 68

8 0

3 years ago

You and your friends decide to camp for one night. Look at the diagram of your tent below. It is drawn on 1 cm squared paper. Th

Citrus2011 [14]

Answer:

1.Area of Porch =2.5m²

2.Number of people =3 people

Step-by-step explanation:

The porch area from the diagram has a dimension of 4 units by 10 units

One units =1cm

Thus the porch is drawn with dimensions of 4cm by 10 cm

Taking length is 10 cm and width as 4 cm, convert these dimensions according to the scale.

The scale is 1cm=0.25m

The width will be= 0.25×4=1 m

The length will be=0.25×10= 2.5m

Area of the porch is given by the formula;

length×width because its has a shape of a rectangle

Area of porch will be

=1m ×2.5m =2.5m²

2.

Find the dimensions of the tent

14 units by 10 units

Applying the scale on the dimensions by multiplying by 0.25

14×0.25=3.5m

10×0.25=2.5m

Width=2.5m

length=3.5m

Subtract the edge distance on both the length and width

Length will be=3.5-(0.25×2)=3.0m

Width will be=2.5-(0.25×2)=2.0m

Find the area remaining to be covered by the people while sleeping

=3.0×2.0=6m²

Area covered by sleeping bag and a ground mat

2m×1m=2m²

Number of people that can sleep in the tent

6m²÷2m²=3 people

8 0

3 years ago

Read 2 more answers

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

Irina18 [472]

Answer:

36

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

and $289=17^2$

$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

3 0

3 years ago

I can't solve number 12. If you solve the others, much appreciated.

saul85 [17]

Answer is 18 due to the theory cause

5 0

2 years ago

(1.1.8 in the book) Let P be the proposition ’I bought a lottery ticket this weekend’ and Q be the proposition ’I won the millio

Karolina [17]

Answer:

~ is for negation

^ is for "and"

v is for "or"

=> for "if then"

<=> for "if and only if"

Step-by-step explanation:

(a) ~P (negation of P)

I didn't buy a lottery ticket this weekend.

(b) P v Q (P is in disjunction Q)

I have either bought a lottery ticket this weekend or won the million dollar jackpot.

(c) P => Q (Q is a consequence of P)

I won the million dollar jackpot because I bought a lottery ticket this weekend.

(d) P ^ Q (P is in conjunction with Q)

I bought a lottery ticket this weekend, and I won the million dollar jackpot.

(e) P <=> Q (P and Q are dependent on each other)

If only I had bought a lottery ticket this weekend, I would have won the million dollar jackpot.

(f) ~P => ~Q (negation of Q is a consequence of negation of P)

I didn't win the million dollar jackpot because I didn't buy a lottery ticket this weekend.

(g) ~P ^ ~Q (negation of P is in conjunction with negation of Q)

I neither bought a lottery ticket this weekend nor won the million dollar jackpot.

(h) ~P v (P ^ Q)

This is logically equivalent to (~P v P) ^ (~P v Q) (negation of P is in disjunction with P, and also with disjunction with Q), and can be best expressed as:

It didn't matter that I bought a jackpot ticket or not, I won the million dollar jackpot.

8 0

3 years ago