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Andrew [12]
3 years ago
8

Francine is making a necklace that has 1 blue Bead for every 6 white beads how many white beads with she use if she uses 11 blue

Beads
Mathematics
2 answers:
uysha [10]3 years ago
7 0

Answer:

66

Step-by-step explanation:

for every 6 white beads there is 1 blue bead

1 times 6 equals 6

therefore

for ____ white beads there are 11 blue beads

11 times 6 equals 66

for 66 white beads there are 11 blue beads

il63 [147K]3 years ago
3 0

Answer:

66

Step-by-step explanation:

If you have 1 for every 6, youll have 1/6 the amount of blue as white. if you have 11, you multiply that by 6, and get 66.

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What number must we multiply by $-\frac23$ to get a product of $\frac34$?
stich3 [128]

Let x be unknown number. If number x is multiplied by -\dfrac{2}{3} and the product is equal to \dfrac{3}{4}, then

x\cdot \left(-\dfrac{2}{3}\right)=\dfrac{3}{4}.

To find x you should divide \dfrac{3}{4} by -\dfrac{2}{3}:

x=\dfrac{\dfrac{3}{4}}{-\dfrac{2}{3}}=\dfrac{3}{4}\cdot \left(-\dfrac{3}{2}\right)=-\dfrac{3\cdot 3}{4\cdot 2}=-\dfrac{9}{8}.

Answer: x=-\dfrac{9}{8}

7 0
3 years ago
Describe how to obtain the graph of f(x)=x+1−−−−−√−2 by transforming the parent graph of f(x) =x√ .
MatroZZZ [7]

Answer: Shift the graph two units down and left one unit.

Step-by-step explanation:

Here the parent function,

f(x) = \sqrt{x}

When the function is shifted left by a factor a then the new function is,

f(x) = \sqrt{x+a}

While when the function is shifted right by a factor A then new function,

f(x) = \sqrt{x-a}

Since here the transformed function is,  f(x) = \sqrt{x+1} - 2

Therefore it was obtained by shifting 1 unit towards left,

Now, when the parent function is shifted vertically upward by a factor a,

Then the new function is, f(x) = \sqrt{x}+a

While, when the parent function is shifted vertically downward by a factor a,

Then the new function is, f(x) = \sqrt{x}-a

Here, the transformed function is,  f(x) = \sqrt{x+1} - 2,

Therefore, it was obtained by shifting 2 unit downward.

Hence, Third Option is correct.

3 0
4 years ago
How to find the asymptotes of a hyperbola?
stellarik [79]
Vertical asymptote:
Find the restriction on x. This is the easiest of the three asymptotes you will need to find (even if only two can show at a time). As a hyperbola is in the form: \frac{1}{x}, you only need to find the restriction on the denominator, namely denominator can never be zero. Hence, let the denominator equal to zero to find the vertical asymptote.

Horizontal asymptote:
Find the restriction on y. To do this, you need to simplify the top and bottom to its lowest terms. If it simplifies to a form such as: a + \frac{b}{x}, then the horizontal asymptote becomes y = a. You need to think to yourself, as x grows to infinite, and shrinks to negative infinite, what happens to the function? Does it slowly curve to a stop?

Oblique asymptote:
This is a pretty rare kind, but it still exists, so don't be naive to this sort of asymptote. This is a form of horizontal and vertical asymptote, only it's at an angle. That is, this asymptote is a set of x and y-coordinates that work in unison to produce a curvature or line.

Let's consider: f(x) = \frac{x^{2} - 6x + 7}{x + 5}

Now, in normal term, a horizontal asymptote would have a degree higher in the denominator than in the numerator. However, it's flipped in this case.

Now, you will need to long divide this set of polynomials to yield a straight y = x line, except it's been moved 11 units to the right to yield a y = x - 11 line.

Remember: these exist because the highest power is in the numerator and not the denominator.
5 0
3 years ago
Omar and Meg just had business cards made. Omar's printing company charged a one-time setup fee of $5 and then $5 per box of car
ivanzaharov [21]

Answer:

5 boxes each

Step-by-step explanation:

4 0
3 years ago
Fill in the blank.
Semenov [28]

O centroid

Step-by-step explanation:

In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side. Every triangle has three medians, one from each vertex, and they all intersect each other at the triangle's centroid.

6 0
3 years ago
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