Francine is making a necklace that has 1 blue Bead for every 6 white beads how many white beads with she use if she uses 11 blue
2 answers:
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In order to arrange the given vectors (u, v, w, x, y, and z) in ascending order of the magnitudes of their vector sums with vector t, you have to follow this procedure:
1) find the coordinates of vector t
2) find the coordinates of the other given vector (u, v, w, x, y, or z)
3) add the corresponding coordinates
4) find the magnitude of the sum vector using the formula
Let's do it:
1) vector t
x-coordinate = 4m/s * cos(60°) = 2 m/s
y-coordinate = 4m/s * sin(60°) = 3.46 m/s
2) u+t
vector u: 3m/s, angle 120°=> second quadrant
x-coordinate = - 3 m/s * cos(60°) = -1.5 m/s
y-coordinate = 3m/s * sin(60°) = 2.6 m/s
u + t:
x-coordinate = 2 - 1.5 = 0.5
y-coordinate = 3.46 + 2.6 = 6.06
3) v + t
vector v: 4.5 m/s , angle 135°
x-coordinate = - 4.5 * cos(180°-135°) = -4.5 * cos(45°) = -3.18
y-coordinate = 4.5 * sin (180° - 135°) = 4.5 * sin(45°) = 3.18
v + t
x-coordinate = 2 - 3.18 = - 1.18
y-coordinate = 3.46 + 3.18 = 6.64
4) w + t
vector w: 4m/s, angle 45°
x-coordinate = 4 * cos(45°) = 2.83
y-coordinate = 4 * sin(45°) = 2.83
vector w + t
x-coordinate = 2+2.83 = 4.83
y-coordinate = 3.46+2.83 = 6.29
5) x + t
vector x: 6 m/s, angle 210°C => third quadrant
x-coordinate = - 6 * cos(30°) = - 5.2
y-coordinate = - 6 * sin(30°) = - 3
x+t
x-coordinate = 2 - 5.2 = - 3.2
y-coordinate = 3.16 - 3 = - 0.16
6) y+t
vector y: 5m/s, angle 330°=> fourth quadrant
x-coordinate = 5 *cos(360° - 330°) = 4.33
y-coordinate = - 5 * sin(30°) = -2.5
vector y+t
x-coordinate = 4.33 + 2 = 6.33
y-coordinate = - 2.5 + 3.46 = 0.96
7) z+t
vector z = 7m/s angle 240° => third quadrant
x-coordinate = - 7 * cos(60°) = - 3.5
y-coordinate = - 7 * sin(60°) = - 6.06
vector z + t
x-coordinate = 2 - 3.5 = - 1.5
y-coordinate = 3.46 - 6.06 = -2.6
magnitude = 3.00
Now, you have all the numbers and just have to order them.
1) find the coordinates of vector t
2) find the coordinates of the other given vector (u, v, w, x, y, or z)
3) add the corresponding coordinates
4) find the magnitude of the sum vector using the formula
Let's do it:
1) vector t
x-coordinate = 4m/s * cos(60°) = 2 m/s
y-coordinate = 4m/s * sin(60°) = 3.46 m/s
2) u+t
vector u: 3m/s, angle 120°=> second quadrant
x-coordinate = - 3 m/s * cos(60°) = -1.5 m/s
y-coordinate = 3m/s * sin(60°) = 2.6 m/s
u + t:
x-coordinate = 2 - 1.5 = 0.5
y-coordinate = 3.46 + 2.6 = 6.06
3) v + t
vector v: 4.5 m/s , angle 135°
x-coordinate = - 4.5 * cos(180°-135°) = -4.5 * cos(45°) = -3.18
y-coordinate = 4.5 * sin (180° - 135°) = 4.5 * sin(45°) = 3.18
v + t
x-coordinate = 2 - 3.18 = - 1.18
y-coordinate = 3.46 + 3.18 = 6.64
4) w + t
vector w: 4m/s, angle 45°
x-coordinate = 4 * cos(45°) = 2.83
y-coordinate = 4 * sin(45°) = 2.83
vector w + t
x-coordinate = 2+2.83 = 4.83
y-coordinate = 3.46+2.83 = 6.29
5) x + t
vector x: 6 m/s, angle 210°C => third quadrant
x-coordinate = - 6 * cos(30°) = - 5.2
y-coordinate = - 6 * sin(30°) = - 3
x+t
x-coordinate = 2 - 5.2 = - 3.2
y-coordinate = 3.16 - 3 = - 0.16
6) y+t
vector y: 5m/s, angle 330°=> fourth quadrant
x-coordinate = 5 *cos(360° - 330°) = 4.33
y-coordinate = - 5 * sin(30°) = -2.5
vector y+t
x-coordinate = 4.33 + 2 = 6.33
y-coordinate = - 2.5 + 3.46 = 0.96
7) z+t
vector z = 7m/s angle 240° => third quadrant
x-coordinate = - 7 * cos(60°) = - 3.5
y-coordinate = - 7 * sin(60°) = - 6.06
vector z + t
x-coordinate = 2 - 3.5 = - 1.5
y-coordinate = 3.46 - 6.06 = -2.6
magnitude = 3.00
Now, you have all the numbers and just have to order them.
Answer:
Step-by-step explanation:
i just got this one right
the kite has two pairs of congruent sides. using the distance formula, the two shorter sides= (since there are two of those length sides, you multiply it by two). Again with the distance formula, the two longer sides=
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