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aivan3 [116]
2 years ago
7

100 POINTS!!! PLEASE HELP ITS EZ :)

Mathematics
1 answer:
n200080 [17]2 years ago
3 0

In 2.44 seconds lindsey be 30 feet in the air.

<h3>What is Quadratic Equation?</h3>

A quadratic equation is a second-order polynomial equation in a single variable x, ax²+bx+c=0. with a ≠ 0 .

Given:

y= -16x²+33x+45

If the height is 30 feet.

30= -16x²+33x+45

-16x²+33x+45-30=0

-16x²+33x+15=0

16x²-33x-15=0

Solving the quadratic equation

x=-b±√b²-4ac/ 2a

x= 33 ± √2049/32

x= (33+ √2049)/32    and x=33-√2049/32

x=2.44 and -0.3833

Learn more quadratic equation here:

brainly.com/question/2263981

#SPJ1

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Answer:

a

Step-by-step explanation:

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8 0
3 years ago
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Which point lies on the line
Oksi-84 [34.3K]
Y + 8 = 4(x - 5)

distribute the 4 to both x and -5

4(x) = 4x
4(-5) = -20

y + 8 = 4x - 20

isolate the y, subtract 8 from both sides

y + 8 (-8) = 4x - 20 (-8)

y = 4x - 28

plug in the x given, if the y matches the answer given, it is the correct answer.

-8 = 4(5) - 28

-8 = 20 - 28

-8 = -8 (True)

D) (5,-8) should be your answer

hope this helps
7 0
3 years ago
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What is the area of the triangle in centimeters<br> squared?
Rashid [163]

Answer:

A = 112cm²

Step-by-step explanation:

Area of a triangle = (bh) / 2

b = base length and h  = height

The triangle shown has a given base length of 14cm and a given height of 16cm

Hence area = ( 16 * 14 ) / 2

16 * 14 = 224

224 / 2 = 112

A = 112cm²

7 0
3 years ago
At the arcade, Jamal had 6 tickets that he had saved from last time he went. This time he played the same game 7 times and earne
melomori [17]

Answer:

Jamal has 111 tickets.

Step-by-step explanation:

Start by knowing that he has 6 tickets he got previously, and then he gets 15 more tickets each time he played the game, which was 7 times.

7 x 15 + 6 = 111

6 0
3 years ago
Find the distance between the point (3, 5) and a line with the equation 5 x - 3 y + 10 = 0
timama [110]

The distance between the point (3, 5) and a line with the equation 5x – 3y + 10 = 0 will be 10 / √(34) units.

<h3>What is the distance between a point and a line?</h3>

Let (x₁, y₁) be the point and ax + by + c = 0 be the line.

Then the distance between a point and a line will be

\rm d = \dfrac{|ax_1 + by_1 + c|}{\sqrt{a^2 + b^2}}

The point (3, 5) and a line with the equation 5x – 3y + 10 = 0.

Then the distance between them will be

\rm d = \dfrac{|5 *3 - 3 *5 + 10|}{\sqrt{5^2 + (-3)^2}}\\d = \dfrac{10 }{\sqrt{34}} \ units

Learn more about the distance between a point and a line here;

brainly.com/question/11558698

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7 0
2 years ago
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