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kumpel [21]
3 years ago
6

Harvey the hamster can run 3 and 1/6 km in 1/4 of an hour. What is his average speed in kilometers per hour?

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0
<h3>Answer:  12 & 2/3 km per hour</h3>

In decimal form, this is approximately 12.667 km per hour.

As an improper fraction, 12 & 2/3 = 38/3

==================================================

Explanation:

Let's use this formula

a & b/c = (a*c+b)/c

to convert the given mixed number to an improper fraction.

3 & 1/6 = (3*6+1)/6

3 & 1/6 = 19/6

The mixed number 3 & 1/6 is the same as the improper fraction 19/6

The hamster runs 19/6 km in 1/4 of an hour.

We can express that as the ratio

19/6 km : 1/4 hr

Multiply both parts by 4 so that the "1/4 hr" turns into "1 hr"

19/6 km : 1/4 hr

4*19/6 km : 4*1/4 hr

76/6 km : 1 hr

38/3 km : 1 hr

Harvey runs 38/3 km in 1 hour

Let's convert that to a mixed number

38/3 leads to a decimal, but 36/3 leads to a whole number

So,

38/3 = (36+2)/3

38/3 = 36/3 + 2/3

38/3 = 12 + 2/3

38/3 = 12 & 2/3

You can use your calculator to note that 38/3 = 12.667 approximately, which is also the value of 12 & 2/3, since 2/3 = 0.667 approximately. This helps confirm we did the conversion correctly.

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Fed [463]

Answer: The range is 16 :)

Step-by-step explanation:

The lowest number is -9 and the highest is 7. the difference between those is 16.

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4 years ago
Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

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