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2 years ago

12

Bill spent a total of $35 at the grocery store. Of this amount, he spent $28 on fruit. What percentage of the total did he spend

1 answer:

Alenkinab [10]2 years ago

4 0

Answer:

80%

Step-by-step explanation:

28/35 as a percent =

First, simplify the fraction.

28/35 = 4/5

Next, turn the simplified fraction into a denominator of 100.

4/5 = 80/100

80/100 = 80%

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What is the sum of an 8-term geometric series if the first term is -11, the last term is 859,375, and the common ratio is -5?

NikAS [45]

Formula of the sum of the 1st nth term in a Geometric Progression:

Sum = a₁(1-rⁿ)/(1-r), where a₁ = 1st term, r = common ratio and n= rank nth of term (r≠1)

Sum = (-11)[1-(-5⁸)] /[(1-(-5)]

Sum = (-11)(1- 390625)/(6)

SUM = 716,144

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2 years ago

21 is 75% of what see answer

aniked [119]

Answer:

84

Step-by-step explanation:

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2 years ago

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Which statement is modeled by the expression?

Afina-wow [57]

A librarian has 150 books to be placed on shelves with an equal number of books on each shelf. If k is the number of shelves to be used, then 150/k is the number of books on each shelf.

Example : lets say there are 10 shelves.....so k = 10
150/10 = 15 books on each shelf.

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2 years ago

Read 2 more answers

Harman [31]

Answer:

we get $\mathbf{gf(2)=-\frac{1}{3}}$

Step-by-step explanation:

We are given:

$f(x)=1-2x\\g(x)= \frac{1}{x}\\h(x)=x^3+1$

We need to find value of $gf(2)$

$gf(2)=g(f(2))$

First putting f(x) inside of g(x) and then putting x=2

$gf(x)=g(f(x))\\gf(x)=\frac{1}{1-2x}$

Now putting x=2 to find $gf(2)$

$gf(x)=\frac{1}{1-2x}\\gf(2)=\frac{1}{1-2(2)}\\gf(2)=\frac{1}{1-4}\\gf(2)=\frac{1}{-3}\\gf(2)=-\frac{1}{3}$

So, we get $\mathbf{gf(2)=-\frac{1}{3}}$

3 0

2 years ago

∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are

son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

In ΔABC

∴ The congruent sides are AB and AC respectively

CB =12 ft. 4 in.=148 in.
AB= $\frac{3}{4}$ CB =111 in. =9 ft. 3 in.
AC= $\frac{3}{4}$ CB =111 in. =9 ft. 3 in.

∵ <em>Perimeter of ΔABC</em> =AB+AC+CB

=9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

=30 ft. 10 in.

2. In ΔDEF

∴ The congruent sides are DE and DF respectively

DE = 6 ft. 3 in. =75 in.
DF = 6 ft. 3 in. =75 in.
Let the length of FE is equal to x
0.75FE =DE =DF
0.75x = 6 ft. 3 in. =75 in.
x =100 in. =8 ft. 4 in.

∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

= 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

= 20 ft. 10 in.

3. In ΔJKL

∴ The congruent sides are JL and KL respectively

JK = x+3
KL =4x-17
JL =6x-45
JL≅KL
4x-17 =6x-45 . . . . . . . . . . . . . . . . . . . . . . . (1)
Subracting 4x from both sides from eq 1
-17 =2x-45
Adding 45 on both the sides
28 =2x
Dividing by 2 on both sides
14 =x
JK = 14+3 =17
KL = 4×14-17 =39
JL = 6×14-45 =39

∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

6 0

3 years ago