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Alinara [238K]
3 years ago
13

In GeoTown, there are 210 teenagers that own a tablet. This is at least 4/5 of all teenagers that live in GeoTown. What is the m

aximum number of teenagers who live in GeoTown?
Mathematics
1 answer:
hoa [83]3 years ago
7 0
252, 210 divided by 5 = 42, 42 x 5 = 210 + 42= 252
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comparing to fractions with the same numerator you look at the doniminater cause the fraction with the greater numerator is grea
lorasvet [3.4K]
Numerator divided by denominator turns it into a fraction

8 0
3 years ago
Using pythagorean therom whats the answer ??<br> a2 + b2 = c2
swat32
By using Pythagorean Theorem,
C^2= (10)^2+ (9)^2
C^2=100 + 81
C^2=181
C= 13.4cm

Hope it helps!
5 0
3 years ago
Can you guys help me? :-(
VMariaS [17]

Answer:

\frac{9}{10}

Step-by-step explanation:

Find the LCD because like last time, you cannot add or subtract fractions with different denominators.

LCD = 10

Since the second fractions stayed at the same denominator, you will only have to multiply the first fraction.

\frac{2 * 2}{5 * 2}

\frac{4}{10}

\frac{4 + 5}{10}

= \frac{9}{10}

5 0
3 years ago
Read 2 more answers
Which equation represents the formula for the general term, gn, of the geometric sequence 3, 1, 1/3, 1/9, . . .?
dedylja [7]

Answer:

Explicit form: g_n=3(\frac{1}{3})^{n-1}

Recursive form: g_n=\frac{1}{3}g_{n-1} with g_1=3.

Step-by-step explanation:

The first term is 3 and we are dividing by 3 each time.

Another way to say we are dividing by 3 each time is to say we are multiplying by factors of 1/3.

If the first term is a and r is the common ratio then the geometric sequence in explicit form is:

a_n=a(r)^{n-1}

g_n=3(\frac{1}{3})^{n-1}

The recursive form for a geometric sequence is a_n=ra_{n-1} with a_1=a where r is the common ratio and a is the first term.

So the recursive form for our sequence is g_n=\frac{1}{3}g_{n-1} with g_1=3.

6 0
3 years ago
What is $29000; 4% decrease
motikmotik
29000 x 0.04 = 1,160
29000 - 1,160 = answer
27,840 = answer 
ur welcome :) be friends with me if you want me to help you in the future :)
6 0
3 years ago
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