Two changes would make this reaction reactant-favored
C. Increasing the temperature
D. Reducing the pressure
<h3>Further explanation</h3>
Given
Reaction
2H₂ + O₂ ⇒ 2H₂0 + energy
Required
Two changes would make this reaction reactant-favored
Solution
The formation of H₂O is an exothermic reaction (releases heat)
If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)
While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient
in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2
As the temperature rises, the equilibrium will shift towards the endothermic reaction, so the reaction shifts to the left towards H₂ + O₂( reactant-favored)
And reducing the pressure, then the reaction shifts to the left H₂ + O₂( reactant-favored)⇒the number of coefficients is greater
The answer is (3)
I always use the acronym SNAP
S- symmetrical is
N- Non-polar
A- asymmetrical is
P-Polar
Answer:
12.5 gm left
Explanation:
30 minutes is THREE half lives
1/2^3 = 1/8th would be left
100g * 1/8 = 12.5 gm
False - A producer always provides food for the consumer.
Answer is: <span>the emitted particle is
an alpha particle.
</span>
Nuclear reaction: ¹⁶O + p⁺
→ ¹³N + α (alpha particle).<span>
Alpha decay is radioactive decay in which an atomic nucleus emits
an alpha particle (helium nucleus) and transforms into an atom
with an atomic number that is reduced by two and mass
number that is reduced by four.
When oxygen-16 gain one proton, atomic mass is 17, but when lose alpha particle
atomic mass reduces by four to 13.</span>
