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Artist 52 [7]
3 years ago
10

If 50.0 ml of a stock sulfuric acid solution whose molarity is 15.0 M is diluted until the molarity of the new solution is 2.50

M what is the volume of the new solution
Chemistry
1 answer:
ser-zykov [4K]3 years ago
7 0
The  volume   of the new solution  is  calculated   using the formula  below

M1V1 = M2V2
M1= 15.0 M
V1= 50.0  ml
M2=2.50 M
V2=?

V2=M1V1/V2

=50  ml  x 15m/2.5 M  =300 ML
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8.1moles

Explanation:

Given parameters:

Mass of water to be decomposed = 29.2g

Unknown:

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Solution:

To solve this problem, we first write the balanced reaction equation :

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Now convert the given mass of the water to number of moles;

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  Number of moles of water = \frac{29.2}{18}  = 16.2moles

   From the balanced reaction equation:

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   16.2 mole of water will produce   \frac{16.2}{2}  = 8.1moles of oxygen gas

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IceJOKER [234]

One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.

As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.

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Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.

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Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1

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