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Artist 52 [7]
3 years ago
10

If 50.0 ml of a stock sulfuric acid solution whose molarity is 15.0 M is diluted until the molarity of the new solution is 2.50

M what is the volume of the new solution
Chemistry
1 answer:
ser-zykov [4K]3 years ago
7 0
The  volume   of the new solution  is  calculated   using the formula  below

M1V1 = M2V2
M1= 15.0 M
V1= 50.0  ml
M2=2.50 M
V2=?

V2=M1V1/V2

=50  ml  x 15m/2.5 M  =300 ML
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