The percentage error is given by multiplying relative error by 100%.
Therefore, to get the percentage error we need relative error which is given by dividing the absolute error with the actual value.
Absolute error = 0.133
Percentage error = 0.133/5.586 × 100%
= 2.38%
The percentage error is therefore; 2.38%
Answer:
V₂ = 285 mL
Explanation:
Given data:
Initial volume of bag = 250 mL
Initial temperature = 19.0°C
Final temperature = 60.0°C
Final volume = ?
Solution:
The given problem will be solved by using Charles Law,
This law stated that " The volume of given amount of gas at constant pressure and constant number of moles is directly proportional to its temperature"
Mathematical relationship:
V₁/T₁ = V₂/T₂
Now we will convert the temperature into kelvin.
Initial temperature = 19.0 + 273 = 292K
Final temperature = 60.0 + 273 = 333K
Now we will put the values in formula:
V₁/T₁ = V₂/T₂
250 mL / 292K = V₂/ 333K
0.856 mL /K = V₂/ 333K
V₂ = 0.86×333K. mL /K
V₂ = 285 mL
Its molecular formula : C₆H₁₂O₆
<h3>Further explanation </h3>
The empirical formula(EF) is the smallest comparison of atoms of compound forming elements.
A molecular formula(MF) is a formula that shows the number of atomic elements that make up a compound.
(EF) n = MF
its empirical formula is CH₂O
CH₂O : 12+2+16=30
![\tt [30]n=180\rightarrow n=6\\\\(CH_2O]_6=C_6H_{12}O_6](https://tex.z-dn.net/?f=%5Ctt%20%5B30%5Dn%3D180%5Crightarrow%20n%3D6%5C%5C%5C%5C%28CH_2O%5D_6%3DC_6H_%7B12%7DO_6)
Answer:
0.3 s.
Explanation:
Half-life of a first order reaction is defined as the the time taken for any fraction of the reaction to complete is independent of the initial concentration.
Half-life of a first order reaction, t° = 0.693/k
where,
t° = half-life of the reaction
k = rate constant
= 2.3 s^-1
Therefore,
t° = 0.693/2.3
= 0.30 s.
