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Trava [24]
3 years ago
10

State and explain the observations when chlorine gas is bubbled through a solution of

Chemistry
1 answer:
natta225 [31]3 years ago
5 0

Answer:

A reduction-oxidation (redox) reaction will occur.

Chlorine gas (Cl2) will accept electrons to form Cl- ions.

The Iron(II) ions (Fe2+) will lose electrons to form Fe3+ ions. (Iron (III) ions)

Fe2+ ions are green, while Fe3+ ions are yellow,

so the observation will be the solution turning from green to yellow.

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How many formula units in 3.56 g magnesium phosphate
Rudik [331]

Answer:

1.5 of mag 1 phos 1 oxygen

Explanation:

hope this helps well sorry i don't really know lol i tried

6 0
3 years ago
Help me with all 6 question
Nitella [24]
Why did you post this again? Because you're lazy and wanted people to not see my post? Once again, ONE QUESTION AT A TIME. We're here to help you with a tough question or work you through it, not do all your homework.
8 0
2 years ago
Read 2 more answers
Calculate the concentration of clo2− at equilibrium if the initial concentration of hclo2 is 2. 25×10^−2 m.
jek_recluse [69]

The concentration of ClO₂⁻ at equilibrium if the initial concentration of  HClO₂ is 0.0654.

<h3>What is concentration?</h3>

The concentration of any substance is the quantity of that substance in per square of the space or container.

The reaction is

HClO₂ + H₂O <=> H₃O⁺ + ClO₂⁻

The pH is 0.454 M

Ka = [H₃O⁺][ClO₂⁻ ] / [HClO₂]

2. 25 × 10⁻² m = [x][x] / 0.454-x]

2 + 0.011 - 0.004994 = 0

solve the quadratic equation

x = 0.0654 = [H3O+] = [ClO2-]

pH = -log (H3O+)

pH = -log(0.0654)

pH = 1.2

equilibrium concentrations of

[HClO2] = 0.454 -x = 0.454 -0.0654 = 0.3886 M

[ClO2- ] = x = 0.0654

Thus, the equilibrium concentrations  is 0.0654.

To learn more about concentration, refer to the link:

brainly.com/question/16645766

#SPJ4

6 0
1 year ago
Consider a situation in which 211 g
Stella [2.4K]

Answer:

3.00 mol

Explanation:

Given data:

Mass of P₄ = 211 g

Mass of oxygen = 240 g

Moles of P₂O₅ = ?

Solution:

Chemical equation:

P₄ + 5O₂       →     2P₂O₅

Number of moles of P₄:

Number of moles = mass/ molar mass

Number of moles = 211 g / 123.88 g/mol

Number of moles = 1.7 mol

Number of moles of O₂ :

Number of moles = mass/ molar mass

Number of moles = 240 g / 32g/mol

Number of moles = 7.5 mol

Now we will compare the moles of product with reactant.

                       O₂         :         P₂O₅

                        5          :           2

                        7.5       :        2/5×7.5 = 3.00

                       P₄          :         P₂O₅

                        1           :           2

                       1.7         :       2×1.7 = 3.4 mol

Oxygen is limiting reactant so the number of moles of P₂O₅ are 3.00 mol.

Mass of P₂O₅:

Mass = number of moles × molar mass

Mass = 3 mol ×283.9 g/mol

Mass = 852 g

3 0
2 years ago
Each element has a unique number of ___
Zigmanuir [339]
the answer is protons
4 0
3 years ago
Read 2 more answers
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