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3 years ago

How can circular motion be accelerated when speed is constant?

Physics

1 answer:

Dima020 [189]3 years ago

7 0

Answer:

Correct answer is C: Because direction changes.

Explanation:

Hope you have a wonderful weekend.

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Magnitude of u = 15, direction angle θ = 35° Magnitude of v = 18, direction angle θ = 60° Find the magnitude and direction angle

djverab [1.8K]

Answer:

32.225 and angle is 48.7 degree.

Explanation:

u = 15, θ = 35 degree

v = 18, θ = 60

First represent the u and v in vector form.

u = 15 (Cos 35 i + Sin 35 j ) = 12.287 i + 8.6 j

v = 18 ( Cos 60 i + Sin 60 j ) = 9 i + 15.6 j

The sum of the two vectors is given by

u + v = 12.287 i + 8.6 j + 9 i + 15.6 j = 21.28 i + 24.2 j

Magnitude of u + v = $\sqrt{21.28^{2}+24.2^{2}}$ = 32.225

Let Ф be the angle

tan Ф = 24.2 / 21.28

Ф = 48.7 degree

5 0

3 years ago

A researcher measures the thickness of a layer of benzene (nn = 1.50) floating on water by shining monochromatic light onto the

baherus [9]

Answer:

The minimum thickness is $t= 8.75*10^{-8} m$

Explanation:

generally the equation for thin film interference is mathematically represented as

$2nt = (m + \frac{1}{2} ) \lambda$

Where t the thickness

m is any integer

n is the refractive index of the film

$\lambda$ is the wavelength of light

Since we are looking for the thickness we make t the subject of the formula

$t = \frac{(m+ \frac{1}{2} ) \lambda}{2n}$

m= 0 cause the thickness is minimum at m=0

Substituting values

$t = \frac{(0 +\frac{1}{2}) 8525*10^{-9} }{2 *1.5}$

$t= 8.75*10^{-8} m$

8 0

3 years ago

Read 2 more answers

A coil of conducting wire carries a current of i(t) = 14.0 sin(1.15 ✕ 103t), where i is in amperes and t is in seconds. A second

Advocard [28]

Answer:

The peak emf in second coil is 1.876 V

Explanation:

Given :

Inductance $L = 130 \times 10^{-6}$ H

The current $I(t) = 14 \sin(1.15\times 10^{3} t)$

We compare above equation with standard equation,

$I(t) = I_{o} \sin (\omega t + \phi)$

From above equation we have,

$\omega = 10^{3}$ and $\phi = 1.15$

Find the inductive resistance,

$X_{L} = \omega L$

$X_{L} = 10^{3} \times 130 \times 10^{-6}$

$X_{L} = 0.134$

The peak emf in second coil is,

$V = I_{o} X_{L}$

$V = 14 \times 0.134$

$V = 1.876$ V

Therefore, the peak emf in second coil is 1.876 V

8 0

4 years ago

What might be done to prevent acid rain damage to objects made from metal and carbonate, such as limestone? Identify a metal obj

serg [7]

Answer: Bronze is a metal that can be damaged in acid rain. It is harsh to metals by almost burning them and may create rust. Everbrite is a clear, protective coating that will seal metal and bronze.

Explanation:

I know this is correct i have done all the research

7 0

3 years ago

A beachgoer leaves a pair of sandals on the shore while she swims. When she puts the sandals on again, the bottom of her feet wi

Vadim26 [7]

Well if shes at a beach i would think that the sun is out and because of radiation they're gonna get hot. somebody should probably warn her or she's gonna burn her feet

4 0

4 years ago

Read 2 more answers