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DerKrebs [107]
3 years ago
9

What is the wavelength of a proton traveling at a speed of 6.21 km/s? what would be the region of the spectrum for electromagnet

ic radiation of this wavelength?
Physics
1 answer:
lukranit [14]3 years ago
8 0
<span>The wavelength of a proton traveling at a speed of 6.21 km/s is wavelength = (6.63E-34 Js) / (1.67Eâ’27kg x 6.21E3m/s) = 6.393E-9 m Region of the spectrum for electromagnetic radiation of this wavelength will be Xrays.</span>
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4
tensa zangetsu [6.8K]

Answer:

C. amount of charge on the source charge.

Explanation:

Electric field lines can be defined as a graphical representation of the vector field or electric field.

Basically, it was first introduced by Michael Faraday and it is typically a curve drawn to the tangent of a point is in the direction of the net field acting on each point.

The number, or density, of field lines on a source charge indicate the amount of charge on the source charge. Therefore, the density of field lines on a source charge is directly proportional to quantity of charge on the source.

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2 years ago
HELP!
Angelina_Jolie [31]

Answer:

speed is increasing.

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3 years ago
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if the efficiency of an electric furnace is 96%, then 96% of the input energy is transformed into thermal energy. what is the ot
Nonamiya [84]
It is wasted, most likely as light, in this case, or it is lost during the transport of electricity.
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3 years ago
Movement of a stationary object it's called what?
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7 0
3 years ago
A student (m = 68 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a
Gnesinka [82]

Answer:

5.7141 m

Explanation:

Here the potential and kinetic energy will balance each other

mgh=\frac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}

This is the initial velocity of the system and the final velocity is 0

t = Time taken = 0.04 seconds

F = Force = 18000 N

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}

From Newton's second law

F=ma\\\Rightarrow F=m\frac{v-u}{t}\\\Rightarrow 18000=68\frac{0-\sqrt{2gh}}{0.04}\\\Rightarrow \frac{18000}{68}\times 0.04=-\sqrt{2\times 9.81\times h}\\\Rightarrow 10.58823=-\sqrt{2\times 9.81\times h}

Squarring both sides

112.11061=2\times 9.81\times h\\\Rightarrow h=\frac{112.11061}{2\times 9.81}\\\Rightarrow h=5.7141\ m

The height from which the student fell is 5.7141 m

5 0
3 years ago
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