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DerKrebs [107]
3 years ago
9

What is the wavelength of a proton traveling at a speed of 6.21 km/s? what would be the region of the spectrum for electromagnet

ic radiation of this wavelength?
Physics
1 answer:
lukranit [14]3 years ago
8 0
<span>The wavelength of a proton traveling at a speed of 6.21 km/s is wavelength = (6.63E-34 Js) / (1.67Eâ’27kg x 6.21E3m/s) = 6.393E-9 m Region of the spectrum for electromagnetic radiation of this wavelength will be Xrays.</span>
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A first-order reaction has a rate constant of 0.241/min. if the initial concentration of a is 0.859 m, what is the concentration
nordsb [41]

Answer: 0.077 M

Explanation:

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant = 0.241minute^{-1}

t = time taken for decay process = 10 minutes

a = initial amount of the reactant= 0.859 M

a - x = amount left after decay process =?

Putting values in above equation, we get:

0.241 minutes^{-1}=\frac{2.303}{10.0}\log\frac{0.859}{a-x}

(a-x)=0.077M

Thus the concentration of a after 10.0 minutes is 0.077 M.


5 0
2 years ago
Read 2 more answers
Please help on these questions!!!
tatiyna

-- First question . . . first answer choice

-- Second question . . . second answer choice

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8 0
2 years ago
The type of function that describes the amplitude of damped oscillatory motion is _______. The type of function that describes t
Salsk061 [2.6K]

Answer:

exponential

Explanation:

type of function that describes the amplitude of damped oscillatory motion is exponential because as we know that here function is

y = A × e^{\frac{-bt}{2m}}  × cos(ωt + ∅ )    ..................................... ( 1 )          

here function A × e^{\frac{-bt}{2m}}   is amplitude

as per equation ( 1 )it is exponential

so that we can say that amplitude of damped oscillatory motion is exponential

8 0
3 years ago
When do phase transitions occur in molecules?
jekas [21]
It occurs when energy is supplied or withdrawn :)
5 0
3 years ago
A 55 meter rope is lying on the floor and has has a weight of 4040 N in total. How much work is required to lift up one end of t
Kazeer [188]

Answer:

Explanation:

Given

Length of rope L=55\ m

Weight of rope W=4040\ N

weight density \lambda =\frac{4040}{55}=73.45\ N/m

Work done to lift rope 33 m

W=\int_{0}^{33}\lambda hdh

W=\int_{0}^{33}73.45hdh

W=73.45\left [ \left ( \frac{h^2}{2}\right )\right ]^{33}_0

W=39.993\ kJ      

6 0
3 years ago
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