The recoil speed of the cannon is 3 m/s.
<u>Explanation:</u>
Law of conservation of momentum is used to find the recoil speed of the cannon.
m₁v₁ = -m₂v₂
m₁= mass of clown = 100 kg
v₁ = speed of the clown = 15 m/s
m₂= mass of the cannon = 500 kg
v₂ = speed of the cannon = ?
Plugin the values, we will get,
v₂ = m₁v₁ / -m₂ = -100×15/ 500 = -1500 / 500 = 3 m/s
So the recoil speed of the cannon is 3 m/s.
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A) Mind you before your reaction time, you had be going at a uniform speed 18m/s, so for the reaction time of 0.5 seconds, you had covered a distance of:
18m/s*0.5s = 9 m
For the second part which involved deceleration, using:
v = u - at, Noting that there is deceleration.
u = 18m/s, v = final velocity = 0, a = -12m/s².
Let us solve for the time.
<span>v = u + at
</span>
0 = 18 - 12*t
12t = 18
t = 18/12 = 1.5 seconds.
Let us compute for the distance covered during the 1.5s
s = ut + 1/2at², a = -12 m/s²
s = 18*1.5 -0.5*12*1.5² = 13.5m
So the total distance covered = Distance covered from reaction time + Distance covered from deceleration
= 9m + 13.5m = 22.5m
So you have covered 22.5m out of the initial 39m.
Distance between you and the dear: 39 - 22.5 = 6.5m
So you have 6.5m between you and the deer. So you did not hit the deer.
b) Maximum speed you still have:
Well through trial and error, if you maintain the same values of deceleration, reaction time, distance between the car and the deer, you could have a speed of 25 m/s and still not hit the deer. Once it is higher than that by a significant amount you would hit the deer.
Objects that are free to move "fall" towards the center of the Earth because of
the gravitational forces that attract the Earth and the object toward each other.
An object on or near the surface of the Earth that has only the force of gravity
and no other forces acting on it accelerates steadily toward the center of the
Earth at the rate of 9.81 meters per second every second.
At the same time, of course, the Earth accelerates toward the object, although
at a considerably lower rate.
Answer:
118.8 N
Explanation:
Weight of the light, W = 214.8 N
Angle between two wires, 2θ = 129.4°
Let t be the tension in each wire. Now the vertical components of tension is balanced by the weight of the light.
2 T Sinθ = W
2 x T x Sin 64.7° = 214.8
1.808 T = 214.8
T = 118.8 N
Thus, the tension in each wire is 118.8 N.