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Vinvika [58]
3 years ago
9

What is the formula for force

Physics
1 answer:
tresset_1 [31]3 years ago
6 0

Force = Mass * Acceleration

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I really need help with this, i dont know what to do first, PLEASE I NEED HELP DUE TOMORROW!!!
enot [183]

Can I tell you what makes this problem so hard ?

It's having all the data WITHOUT HAVING THE STORY !

We first have to figure out what all those things are.  I mean, we don't even know what  F  is, what  d  is, what  Kef  or  Vi  is, or how  W  figures in to the whole thing.  You really have no mercy !

If my hunch is correct, the story goes like this:

-- There's an object sailing along, minding its own business, not bothering anybody, and its speed is 7.2 meters per second.

-- Somebody jumps out in front of the object and begins to push back on it with 215 Newtons of force, trying to slow it down and stop it.

-- The object is only able to go another 13 meters, pushing the guy backwards but slowing down, and then it stops.

-- The question is:  What is the mass of the object ?

Now I'll go ahead and solve the problem that I just invented:

-- Kinetic energy = (1/2) (mass) (speed²)

Before anybody touched it, the object's kinetic energy was

KE = (1/2) (mass) (7.2 m/s)²

KE = (25.92) x (mass)

-- Since that's the energy the object had, THAT's how much work the guy has to do in order to make the object stop.

Work = (force) x (distance)

Work = (215 N) x (13 meters)

Work = 2,795 N-m

-- And there you go.  The work the guy did to stop the object is the amount of energy the object had before he came along.

(25.92) x (mass of the object) = 2,795 N-m

Divide each side by 25.92:

Mass of the object = (2,795 N-m) / (25.92)

<em>Mass = 107.83 kilograms</em>

5 0
3 years ago
SI units are useful because they are all related by multiples of ____. a. two c. 10 b. five d. 50
Kryger [21]
The answer is b to the question
4 0
3 years ago
What is the usual time ice takes to evaporate above a Bunsen burner?
Step2247 [10]
Depends on the volume but a normal ice cube takes less than 20 seconds
5 0
3 years ago
A man weighing 700 NN and a woman weighing 440 NN have the same momentum. What is the ratio of the man's kinetic energy KmKmK_m
Eduardwww [97]

Answer:

The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

Explanation:

Given;

weight of the man, W = 700 N

Weight of the woman, W = 440 N

momentum is given by;

P = mv\\\\v = \frac{P}{m}

Kinetic energy of the man;

K_m = \frac{1}{2}m_m(\frac{P_m}{m_m})^2  \\\\K_m = \frac{P_m^2}{2m_m}

Momentum of the man is calculated as;

P_m^2 = 2m_mK_m

The kinetic energy of the woman is given by;

K_w = \frac{P_w^2}{2m_w}

The momentum of the woman is given;

P_w^2 = 2m_wK_w

Since, momentum of the man = momentum of the woman

P_m^2 = P_w^2

2m_mK_m = 2m_wK_w\\\\\frac{K_m}{K_w} = \frac{2m_w}{2m_m}\\\\\frac{K_m}{K_w} = \frac{m_w}{m_m}

mass of the mas = 700 / 9.8 = 71.429

mass of the woman is = 440 / 9.8 = 44.898

\frac{K_m}{K_w} = \frac{44.898}{71.429}\\\\\frac{K_m}{K_w} =0.629

Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

3 0
3 years ago
A lack of precision in scientific measurement typically arises from?
PtichkaEL [24]

Answer:

limitations of the measuring instrument.

Explanation:

Hope this helps

6 0
2 years ago
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