<span>x^2 + 8x – 48 = 0
That is a quadratic equation where
a = 1
b = 8
c = -48
We can solve it by using the quadratic formula:
x = [-b +-sq root (b^2 - 4ac)] / 2a
x = [-8 +- sq root (64 -4*1*-48)] / 2*1
</span><span>x = [-8 +- sq root (256)] / 2
x = [-8 +-16] / 2
x1 = 8 / 2 = 4
x2 = -24 / 2 = -12
</span>
First you need to convert the mixed numerals to improper fractions , for example 1 1/3 = 1/3 + 3/3 = 4/3. Then you multiple across the numerators, the top number, and then the denominator, the bottom number. Simplify the answer if necessary.
1 1/3 x 5/6
4/3 x 5/6 = 20/18 Divide numerator and denominator by 2
10/9 write as a mixed number 1 1/9
AC is common between triangle ABC and triangle CDA...
Angle ABC=angle CDA ( opposite angles in parallelogram are equal)
So both triangles are congruent ( 1 common line and 2 equal angles)
First, subtract 14 from both sides. then, divide both sides by two to get X=4
Answer:
Step-by-step explanation:
Common difference is 3.
Let x be a term in the sequence. The next term in the sequence is x+3.
x(x+3) = 598
x² + 3x - 598 = 0
x = [-3 ± √(3²-4⋅1(-598))]/[2⋅1] = [-3 ± 49]/2 = 23, -26
-26 is an extraneous solution, so x = 23.
The two terms are 23 and 26.
