Solve the equation 8 sin x = 2.5 for
the interval 0° to 720°
1 answer:
Answer:
<em>18.2°, 161.8° and 378.2°</em>
Step-by-step explanation:
Given the expression:
8 sin x = 2.5
Divide both sides by 8
sinx = 2.5/8
Sinx = 0.3125
x = arcsin(0.3125)
x1 = 18.2
Since sin theta is positive in the second quadrant, x2 = 180 - 18.2 = 161.8°
Since our angle must lie in between 0° and 720°,then;
x3 = 360 + 18.2 = 378.2°
<em>Hence the required angles are 18.2°, 161.8° and 378.2°</em>
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