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Lelechka [254]
2 years ago
14

What's answersBMIweight 1.62 (5'4")height 46 kg (102 Ibs)answers​

Mathematics
2 answers:
Vesna [10]2 years ago
6 0

Step-by-step explanation:

bmi formula is

703* weight/height^2

5*12+4 = 64 height in inches

703 * 102/64^2 = 17.5

sergey [27]2 years ago
5 0

Answer:

17.5 (underweight)

Step-by-step explanation:

BMI= Weight (kg)/Height(m)²

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The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 60 o
Gala2k [10]

Answer:

Step-by-step explanation:

Given that the Acme Company manufactures widgets, which have a mean of 60 ounces and a standard deviation of 7 ounces

We know that 95% of the area lie between -2 and 2 std deviations from the mean.

i.e. Probability for lying in the middle of 95%

Z score (60+7(-2), 60+7(2))\\=(46, 74)

Between 46 and 74 oz.

b) Between 12 and 57

convert into Z score

(\frac{12-60}{7}

P(-6.86<z<-0.43)

=0.5-0.1664=0.3336

c) X<30 gives Z<-4.83

i.e. P(X<30) =0.00

3 0
3 years ago
Y and x have a proportional relationship, and y = 12 when x = 5. What is the value of y when x = 8?
serious [3.7K]
When x = 8 y = 15

The way to figure this out is to subtract 12 by 5. That’s 7 so there’s a difference of 7 between both of the numbers.

Hope this helped!
8 0
2 years ago
A pack of pencils cost $8, but the price went<br> up to $12. What is the percent of increase?
sp2606 [1]

Answer:

A pack of pencil' price=$8

Price went up=$12

increasing percentage = change/original x100

= (12 -8)/8 x100

=4/8 x100

=50%

6 0
3 years ago
Question 27 <br> Find the length of the hypotenuse. Leave answer in simplest radical form.
skelet666 [1.2K]

Use SOHCAHTOA.  Since we are looking for the hypotenuse, you must use sine or cosine.  Since, we are given the adjacent side, use cosine.

cosx=a/h

cos45=8/h

√2/2=8/h

<em>*Cross multiply*</em>

h√2=16

<em>*Divide both sides by √2*</em>

h=16/√2

<em>*Multiply by √2/√2*</em>

h=(16√2)/2

<em>*Simplify the fraction*</em>

h=8√2

Hope this helps!!

6 0
3 years ago
Find the zeros of polynomial functions and solve polynomials equations.<br> f(x)=2x^3+2x^2-4x
vladimir2022 [97]

f(x)=2x^3+2x^2-4x

The zeros of polynomial functions

2x^3 + 2x^2 - 4x = 0

2x(x^2 + x - 2) = 0

2x(x - 1)(x + 2) = 0

2x = 0; x = 0

x - 1 = 0; x = 1

x + 2 = 0; x = -2

Answer

x = -2 , 0 , 1


4 0
3 years ago
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