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Ivenika [448]
3 years ago
12

Mia practiced violin for 4⅛ hours per day for 5 days. How many hours did she practice?

Mathematics
1 answer:
Xelga [282]3 years ago
5 0

Answer:

20 5/8

Step-by-step explanation:

convert mixed number into decimal by changing mixed number into an improper fraction then dividing

multiple by 5

boom you got your answer:p

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Oh and alsoo can someone plzzzzz add an explanation
Pani-rosa [81]

Answer:

Brian sold 35 tickets

Step-by-step explanation:

42/6 = 7

7 x 5 = 35

35/42 = 5/6

Brian sold 35 tickets

(I know this isn't part of the question, but Brain didn't sell 7 tickets)

5 0
3 years ago
Need help on 9 and 10
Wewaii [24]
9.) The relation can not be a function only if the domain is the same. If you plot the points on a graph and use the Vertical Line Test(VLT) you would see that none of the points would be on the same line. It doesn't matter if the range is the same

10.)On the graph your y-intercept would be 2 so that is where you plot your first point. In order to find the slope you need to go up three spaces and one space to the left this is also known as "rise over run". *Remember you always go up spaces for "rise over run" but if the slope is positive then you go to the right and if its negative you go to the left.

I hope this helps love! :)
4 0
3 years ago
Melissa made $252 for 18 hours of work.
Murljashka [212]
She will make $182 for 13 hours of work
8 0
3 years ago
Read 2 more answers
In a random sample of 8 people, the mean commute time to work was 36.5 minutes and the standard deviation was 7.4 minutes. A 98%
ANEK [815]

Answer:

Step-by-step explanation:

Given that

Sample size = n = 8: sample mean = 36.5 and s = sample std dev = 7.4 minutes

98% CI using t = (28.7, 44.3) with margin of error as 7.8

Now if sigma = population std dev is known we use Z critical value

Margin of error = 2.33*8.7/\sqrt 8 = 7.167

CI = (36.5 ±7.167)

This is not wider than that used using t distribution

The margin of error of u is ___7.167

98% confidence interval using the standard normal distribution is (29.333__,43.667__)

d)the confidence interval found using the standard normal distrubution is narrower than the confidence interval found using the students t-distribution

3 0
3 years ago
-3 1/2 - [-12 1/4]...............................................
nasty-shy [4]

Answer:

8.75

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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