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3 years ago

13

the product of a numer, k, and four is seven more than the quotient of the number and two thirds. write an equation to represent

this situation

1 answer:

pav-90 [236]3 years ago

6 0

I attached a picture with equation because it is easier than attempting to type it out.

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Molly had already read 6 books this year before joining a book club, and she plans to read 3 books every month now that she has

tatuchka [14]

Answer:

12 months

Step-by-step explanation:

Given data:

Before joining club 6 books read

3 books every month

total books read 42

books read after joining the club = 42 - 6

books read after joining the club = 36

Months she has in book club = 36/3

Months she has in book club = 12 months

7 0

3 years ago

I need help finding the domain and range, I already know is not a function

FromTheMoon [43]

Answer:

Domain: [-4, 4]

Range: [-3, 5]

Function? No

Step-by-step explanation:

Domain is all x-values that can be inputted in the graph that returns an output.

Range is all y-values that are outputted when <em>x</em> is inputted.

A function has to pass the Vertical Line Test.

6 0

3 years ago

A problem states: "There are 2 more horses than cows in a field. There are 15 animals in the field in all. How many horses are t

mash [69]

Let h = the number of horses in the field
Let c = number of cows in the field

There are 2 more horses than cows in the field. Therefore
h = c + 2
or
c = h - 2 (1)

There are 15 animals in the field. Therefore
h + c = 15 (2)

Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15

Answer:
The correct equation is
2h - 2 = 15

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge

BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

Read 2 more answers

write an enaquality that expresses the reason the lengths 5 feet , 10 feet and 20 feet could not make a triangle. explain how th

NikAS [45]

For any triangle, the 2 shortest sides added together have to be longer than the longest sides.

short side (10) + short side (5) needs to be greater than (>) longest side (20)

10 + 5 > 20

15 > 20

This inequality is incorrect, so the lengths cannot make a triangle.

Hope this helps :)

7 0

3 years ago