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DanielleElmas [232]
3 years ago
8

You are interested in determining if the average amount of time (in hours) that students spend on the Internet per day is greate

r than 2 hours. The data below are from a random sample of 11 students. 2.5 100 .5 1 1.5 3 3.5 4 3 4 2.5 What did you notice from your preliminary analysis of the data
Mathematics
1 answer:
vova2212 [387]3 years ago
8 0

Answer:

The data is not appropriately normal.

Step-by-step explanation:

In inferential statistics, a normal distribution is said to be symmetric and should be single-peaked when working with a random selection of a large sample.

The high number of the sample is 100 which is further from other samples, the central limit theorem explains that the sample size of independent mean must be large enough to mimic the population for the sample to be normal or nearly normal. So, the sample is not appropriately normal and should be larger in size.

You might be interested in
The data in which table represents a linear function that has a slope of zero? I can’t figure it out
Marianna [84]

Answer:

A

Step-by-step explanation:

Think about it.

y = (0)x + b

this gives

y = b

therefore Y equals a single number regardless of the x value.

This behavior is shown in table A.

3 0
3 years ago
Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)
IrinaK [193]

Answer:

Equation of the circle   (x-3)²+(y-5)²=(6.4)²

                             x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

                   Centre = (\frac{-2+8}{2} ,\frac{1+9}{2} )

               Centre (h, k) = (3 , 5)

<u><em>Step(ii):-</em></u>

The distance of two end points

PQ = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2}  }

PQ= \sqrt{(8+2 )^{2} +(8 )^{2}  }

PQ = √164 = 12.8

Diameter    d = 2r

                 radius r = d/2

                Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle  

                    (x-h)²+(y-k)² = r²

                   (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x  +y² -10y  = 40.96-34

x² -6x  +y² -10y -7= 0

4 0
3 years ago
Jamie has a cup holder that can hold 3 cups at a time. The cup holders are labeled a, b, and c. He has 3 different color cups (b
JulsSmile [24]

Answer:

6 ways.

Step-by-step explanation:

a, b, c

a, c, b

b, a, c

b, c, a

c, a, b

c, b, a

8 0
3 years ago
What percent does 5.2 represent? Round your answers to the nearest tenth of a percent.
dezoksy [38]
5.2 as a percent is 520%
3 0
3 years ago
Determine whether the sequence converges or diverges. If it converges, give the limit.
vaieri [72.5K]

Answer:

The given series converges and \lim_{n \to \infty} a_n =0

Step-by-step explanation:

Given is 108, -18, 3,...

It is an alternate series. An alternate series is convergent if:

1. The series is decreasing.

2. If the last term (n-th term) of series converges to 0.

<u>Since each next term is less than its preceding term, so it is decreasing.</u>

First term, a = 108

Second term = -18

Common ratio, r = -18/108 = -1/6

General term, aₙ = a*rⁿ = 108*(-1/6)ⁿ

<u>When n increases to infinity, the exponent term will decreases to zero, and last term (n-th term) will converge to 0 as well.</u>

Hence, the given series converges.

Now limit will be: \lim_{n \to \infty} a_n

\lim_{n \to \infty} 108*(-1/6)^n \\= 108*(-1/6)^\infty \\= 108*(1/\infty) \\= 108*0 \\= 0

Hence, \lim_{n \to \infty} a_n =0

7 0
3 years ago
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