3 years ago

What are the first three terms of the sequence defined by the following function?

Mathematics

1 answer:

Naily [24]3 years ago

7 0

Answer:

Step-by-step explanation:

$f(n)=41+(n-1)^5\\\\f(1)=41+(1-1)^5=41\\\\f(2)=41+(2-1)^5=41-1=40\\\\f(3)=41+(3-1)^5=41-32=9$

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