Question

What are the first three terms of the sequence defined by the following function?

Answer 1

Answer:

        41, 40 and 9

Step-by-step explanation:

$f(n)=41+(n-1)^5\\\\f(1)=41+(1-1)^5=41\\\\f(2)=41+(2-1)^5=41-1=40\\\\f(3)=41+(3-1)^5=41-32=9$