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Elis [28]
3 years ago
11

Write a story problem that would model the sum of the arrows in the number diagram below. The first part of your story should re

present the bottom line that stops at 9. The second part of your story problem should represent the middle line that goes back to 0. The third part of your story problem should represent the top line which then goes back to 5. Be creative and have fun with this story problem.

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0
ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana
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Solve: 5x-4=6 please help meee
marta [7]

Answer:

x=2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
-70y^2+90x^3+100yx^2-63xy<br>factor by grouping
Alexeev081 [22]
The idea of grouping is to get the terms in groups that allow you to factor out from each group something that becomes a factor in itself, leaving two factors behind that are alike. Like this: rearrange those terms so they are in this order:
(-70y^2 - 63xy) + (90x^3 + 100yx^2).  Now out of the first set we are going to factor out a -7y, and out of the second set we are going to factor out a 10x^2. When we do this, this is what we get: -7y(10y + 9x) + 10x^2(9x + 10y). As you can see, what's inside both sets of parenthesis is the same, just in a different order. We can factor that out now, leaving (9x + 10y)(10x^2 - 7y). And that is factored by grouping.
4 0
3 years ago
In the triangle below, what is the tangent of 45°?
Lana71 [14]

Answer:

C

Step-by-step explanation:

tan45° = \frac{opposite}{adjacent} = \frac{1}{1} = 1

6 0
3 years ago
Read 2 more answers
A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Four hu
castortr0y [4]

<em>Answer: h = 120 ft;    w = 80 ft </em>

<em></em>

<em>A = 9600 ft^2</em>

<em />

<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>

<em></em>

<em>A = h*w   (eq1)</em>

<em></em>

<em>The total amount of fence used is:</em>

<em></em>

<em>L = 2*h + 2*w + w    (eq2)    (an extra distance w beacuse of the division)</em>

<em></em>

<em>Solving for w:</em>

<em></em>

<em>w = L - 2/3*h = 480 - 2/3*h   (eq3)  Replacing this into the area eq:</em>

<em></em>

<em></em>

<em></em>

<em>We derive this and equal zero to find its maximum:</em>

<em></em>

<em>   Solving for h:</em>

<em></em>

<em>h = 120 ft.  Replacing this into eq3:</em>

<em></em>

<em>w = 80ft</em>

<em></em>

<em>Therefore the maximum area is:</em>

<em></em>

<em>A = 9600 ft^2</em>

<em />

5 0
3 years ago
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