2(4 - 2r) = -2(r + 5)
First, divide both sides by -2. / Your problem should look like:
Second, regroup your terms. / Your problem should look like:
Third, add 4 to both sides. / Your problem should look like:
Fourth, add r + 5 + 4 to get r + 9. / Your problem should look like:
Fifth, subtract r from both sides. / Your problem should look like:
Sixth, subtract 2r - r to get r. / Your problem should look like:
Answer:
r = 9
Answer:
9cm
Explicación:
El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:
Donde c es la hipotenusa y a y b son los catetos.
Por lo cual, podemos reemplazar c por 15cm y a por 12cm :
Finalmente , debemos resolver la ecuación para b, así que b es igual a :
Por lo tanto, la longitud del otro cateto es 9 cm
<span>A scale factor is a number which scales, or multiplies, some quantity. The ratio of
any two corresponding lengths in two similar geometric figures is also
called a scale factor.
Given a function
which is formed from the parent function
The function
</span><span>
was obtained from the parent function by multiplying the parent function by 3.
Therefore, the scale factor of the function </span><span>
is 3.</span>
Answer:
all real numbers greater than zero
Step-by-step explanation:
The square root of a number must be greater than or equal to zero
sqrt(x) ≥0
Squaring each side
x ≥0
This means the domain is all real numbers greater than or equal to zero
I would go with all real numbers greater than zero since it is the closest answer
Basically with the example you have you need to have the x and y variables on different sides.
Equation:
-18x+9y=72 (now you want to add 18x on both sides)
<u>+18x +18x
</u><u>9y=72+18x </u> (next you divide 9 to both sides to get x and y alone)
9
y=8+2x (now that you have the x and y alone this is the final equation)
On the graph you want to put a dot on 8 since it's the y-intercept or the starting point of the equation. After that you want to add 2 every time you go by 1 on the x-axis. I have a picture of a graph...
<em>I hope this help you out :D</em>
