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tatuchka [14]
2 years ago
5

My brain is lagging:<​

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
8 0

Distance between two points (-3, 4) and (5, -2) is 10 units.

Mid-point of the line segment joining (-1, -5) and (7, 1) is  (3, -2).

Degree of the given polynomial is 7.

6) Distance between two points (x_1, y_1) and (x_2, y_2) is:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So, distance between two points (-3, 4) and (5, -2) is:

=\sqrt{(5-(-3))^2+(-2-4)^2}

=\sqrt{(8)^2+(-6)^2}

=\sqrt{64+36}

=\sqrt{100}

=10

So, option D is correct.

7) Mid-point of the line segment joining (x_1, y_1) and (x_2, y_2) is:

(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Mid-point of the line segment joining (-1, -5) and (7, 1) is:

(\frac{-1+7}{2}, \frac{-5+1}{2})

= (\frac{6}{2}, \frac{-4}{2})

= (3, -2)

So, option A is correct.

8) Degree of a polynomial is the highest power of the variable in the polynomial.

f(x)=3x^2-7x^4+9x^7+2x^3

Here, the highest power of the variable is 7.

So, option B is correct.

Learn more about distance formula, mid point formula, and degree of polynomial.

brainly.com/question/16319826?referrer=searchResults

brainly.com/question/24147029?referrer=searchResults

brainly.com/question/2284746?referrer=searchResults

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What variable are you solving for?
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N–2=10n+4/2 what is the value of n need help asap
MakcuM [25]
N - 2 = 10n + 4/2

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If this answer is right please leave a thanks and a rating. :)
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3 years ago
The size of the tank a fish collector needs depends on how many fish he has. Which in the independent variable
Semenov [28]

Answer:

Step-by-step explanation:

"<u><em>The size of the tank</em></u> a fish collector needs <u><em>depends</em></u> on <em>how many fish he has</em>."

Dependent variable is the size of the tank.

<em>Independent variable</em> is how many fish a fish collector has.

3 0
2 years ago
A family has two cats named Gordo and Flaco. Gordo weighs 15 pounds and Flaco weighs 8 pounds. A cat’s weight is classified as u
Elena-2011 [213]

Answer:

Gordo's weight = 15 pounds

It is outside the healthy weight range and is in the top 5% of weights of cats.

Gordo's weight makes Gordo unhealthy.

Step-by-step explanation:

μ = mean weight = 9.5 pounds

σ = standard deviation = 1.5 pounds

This is a normal distribution problem

We first calculate the limit of the bottom 5% of weights

Let the z-score for this limit be z'

P(z < z') = 0.05

From the normal distribution table,

z' = -1.645

And the limit for the top 5% which is z" = 1.645.

The weight that corresponds to these scores are then calculated.

Standardized scores are given as

z = (x - μ)/σ

So,

z' = (limit for the bottom 5% - μ)/σ

-1.645 = (limit for the bottom 5% - 9.5)/1.5

limit of the bottom 5% = (-1.645)(1.5) + 9.5 = 7.033 pounds

z" = ( (limit for the top 5% - μ)/σ

1.645 = (limit for the top 5% - 9.5)/1.5

limit of the bottom 5% = (1.645)(1.5) + 9.5 = 11.968 pounds

Therefore the healthy weight range for cats is (7.033 < x < 9.968)

Gordo's weight = 15 pounds

It is outside the healthy weight range and is in the top 5% of weights of cats.

Gordo's weight makes the cat unhealthy.

Flaco's weight = 8 pounds

Flaco's weight lies in the healthy weight range for cats. Hence, Flaco is a healthy cat.

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2 years ago
Solve for B. B x 2 = 36
Drupady [299]

The answer is 18 . Because 36 divided by 2 is 18

3 0
3 years ago
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