All categories

3 years ago

Java !!!

Computers and Technology

1 answer:

coldgirl [10]3 years ago

7 0

Answer:

Explanation:

import java.util.*;

public class BalancedBrackets {

// function to check if brackets are balanced

static boolean isBalanced(String expr)

{

Stack<Character> stack = new Stack<Character>();

for (int i = 0; i < expr.length(); i++)

{

char x = expr.charAt(i);

if (x == '(' || x == '[' || x == '{')

{

// Push the element in the stack

stack.push(x);

continue;

}

if (stack.isEmpty())

return false;

char check;

switch (x) {

case ')':

check = stack.pop();

if (check == '{' || check == '[')

return false;

break;

case '}':

check = stack.pop();

if (check == '(' || check == '[')

return false;

break;

case ']':

check = stack.pop();

if (check == '(' || check == '{')

return false;

break;

}

// Check Empty Stack

return (stack.isEmpty());

}

public static void main(String[] args)

{

Scanner scan = new Scanner(System.in);

System.out.println("\nEnter the expression to check is balanced or not !");

String expr = scan.nextLine();

boolean output;

output = isBalanced(expr);

System.out.println(output);

if (output)

System.out.println("Balanced ");

else

System.out.println("Not Balanced ");

scan.close();

}

You might be interested in

Consider the following class declaration: public class Square { private double sideLength; public double getArea() { return side

kipiarov [429]

Answer:

Here is the constructor:

public Square(double s) { //constructor name is same as class name

sideLength = s; } //s copied into sideLength field

Explanation:

The above constructor is a parameterized constructor which takes a double type variable s as argument. The name of constructor is same as the name of class.This constructor requires one parameters. This means that all declarations of Square objects must pass one argument to the Square() constructor as constructor Square() is called based on the number and types of the arguments passed and the argument passed should be one and of type double.

Here is where the constructor fits:

public class Square {

private double sideLength;

public Square(double s) {

sideLength = s; }

public double getArea() {

return sideLength * sideLength;}

public double getSideLength() {

return sideLength; } }

4 0

3 years ago

The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a

Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"

You can also do this:

punctuation = r"[.?!,;:'-]"

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2 which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re #to use regular expressions

def compare_strings(string1, string2): #function compare_strings that takes two strings as argument and compares them

string1 = string1.lower().strip() # converts the string1 characters to lowercase using lower() method and removes trailing blanks

string2 = string2.lower().strip() # converts the string1 characters to lowercase using lower() method and removes trailing blanks

punctuation = r"[-.?!,;:']" #regular expression for punctuation characters

string1 = re.sub(punctuation, r"", string1) # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

string2 = re.sub(punctuation, r"", string2) # same as above statement but works on string2 as 3rd argument

print('string1:',string1,'\nstring2:',string2) #prints both the strings separated with a new line

return string1 == string2 # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0

4 years ago

8. What is the correct jQuery code to set the background color of all p elements to red?

pickupchik [31]

The correct anwers is the letter b.)

3 0

3 years ago

"which key do you hold down to select a group of contiguous files"

zloy xaker [14]

The "Ctrl" key is the answer.

4 0

3 years ago

Class function which is called automatically as soon as the object is created is called as __

ki77a [65]

Answer: A- Constructor

7 0

3 years ago