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3 years ago

April is making necklaces using beads

Mathematics

1 answer:

BigorU [14]3 years ago

3 0

Step-by-step explanation:

To convert millimeters to centimeters we divide

As, 10 millimeters = 1 centimeter

So 1 centimeter = 1/10 millimeter

So here of we have 6 millimeters, so centimeters = 6/10 = 0.6cm

So the diameter of each bead in the necklace = 0.6cm

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Determine whether each statement is true or false. If false, give a counterexample.

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This statement is true, or else you wouldn't have a sphere.

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3 years ago

Are these correct? If not help me please??

Verizon [17]

Answer: no, no, yes, no, yes, yes

Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

Use the equation a = IaIâ

german

Answer:

a) $\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) $\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

c) $\:\:=7\cdot \frac{\:\:}{7}$

Step-by-step explanation:

a) Let a=<2,1,-3>

The magnitude of a is $|a|=\sqrt{2^2+1^2+(-3)^2}$

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The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{\sqrt{14} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }$

b) Let a=2i - 3j + 4k

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$|a|=\sqrt{4+9+16}=\sqrt{29}$

$\hat{a}=\frac{\:\:}{\sqrt{29} }$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }$

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<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

$|a|=\sqrt{3^2+6^2+(-2)^2}$

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The unit vector in the direction of a is

$\hat{a}=\frac{\:\:}{7}$

Using the relation $a=|a|\hat{a}$ , we have

$\:\:=7\cdot \frac{\:\:}{7}$

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3 years ago

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