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timurjin [86]
3 years ago
6

I am not sure if this is right but some one help me

Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

you are right

Step-by-step explanation:

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Ne4ueva [31]

Hope this helps

x > -17

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the coordinates of a quadrilateral are (5,8), (7,10), (9,12) and (11,14). after a transformation, the sign of the x-coordinate a
BartSMP [9]

Answer:

The quadrilateral is rotated 180° about the origin

Step-by-step explanation:

Lets revise some transformation

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

∴ Its image is (-y , -x)

- If point (x , y) rotated about the origin by angle 90° anti-clock wise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clock wise

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise or

 anti-clockwise around the origin

* In our problem:

- The sign of the x-coordinate and the sign of the y- coordinate

 for each ordered pair have changed

- The image of each point is (-5 , -8) , (-7 , -10) , (-9 , -12) , (-11 , -14)

∴ The quadrilateral is rotated 180° about the origin

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3 years ago
PLEASE HELP!! I'LL GIVE YOU THE BRAINLIEST!!!
disa [49]

1.  C. 130 = 1.5p-50

2. C. $3.19

4.(-6,12); (2,8)

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Hope this helps. :)

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BartSMP [9]

Answer:x=10/3

Step-by-step explanation:

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A restaurant purchased kitchen equipment on January​ 1, 2017. On January​ 1, 2019, the value of the equipment was ​$14 comma 550
timama [110]

Answer:

\frac{dV(t)}{dt} = - 1675.38

Step-by-step explanation:

In 2017, the vakue of the kitchen equipment was $14550

V(0)=$14550

Its value after then was modelled by V(t)=14550e^{-0.158t

We are required to find the rate of change in value on January 1, 2019

V(t)=14550e^{-0.158t

\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t

\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t

\\Let u= -0.158t,\frac{du}{dt}=-0.158

\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}

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In 2019, i.e. 2 years after, t=2

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3 0
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