Answer:
00000
Step-by-step explanation:
Grammar isn't like math,
you have to sound it out to see if it makes sense.
1.splashes
2.fixs
3.catches
4.mix
Answer: Choice B. sqrt(2)
Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how
tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1
Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long
a^2 + b^2 = c^2
(1)^2 + (1)^2 = c^2
2 = c^2
c^2 = 2
c = sqrt(2)
The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with
sec(theta) = hypotenuse/adjacent
sec(theta) = AC/AB
sec(theta) = sqrt(2)/1
sec(theta) = sqrt(2) which is why choice B is the answer
Answer: 235 cm^2
Explanation: you can cut the shape into two smaller ones and then solve for each smaller shapes area. to find out the length of the top piece with 11 as length you can subtract nine from fourteen. from their you calculate the area of the top shape (11x5=55) and then the bottom shape (9x20=180). from their just add the two areas to get 235.