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2 years ago

For 18 i need major help i don't understand what to do

Mathematics

1 answer:

loris [4]2 years ago

4 0

To get the answer, you need to multiply the scale factor with the coordinate(In this case its P).So u need to multiply 6(x coordinate) X 3(Scale factor)= 18
and 2 X 3 = 6.....the Answer is D (18,6).....hope this helps.

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Please help!!

yarga [219]

Because this is a fourth degree that will be tricky to factor as it is, we will do a u substitution. Let $x^2=u$ . We can now rewrite that polynomial in terms of u: $u^2-7u-8=0$ . Filling into the quadratic formula we have $u=\frac{7+/-\sqrt{49-4(1)(-8)}}{2}$ . Simplifying down $u=\frac{7+/-\sqrt{81}}{2}$ and $u=\frac{7+9}{2}$ or $u=\frac{7-9}{2}$ . That means that u = 8 or u = -1. But don't forget that we let $u=x^2$ , so we have to put x-squared back in for u. That gives us $x^2=8$ which simplifies down to $+/-2\sqrt{2}$ . That also gives us $x^2=-1$ . When we take the square root of -1, we have to use the fact that -1 = i^2, so we sub that in to get $x=+/-i$ . All in all, your solutions are as follows: $2\sqrt{2},-2\sqrt{2},i,-i$ which is choice b.

7 0

2 years ago

You rolla fair 6-sided die.

Marizza181 [45]

Answer:dude just use a caculator

Step-by-step explanation:the answer is 200

3 0

2 years ago

What is 6.5% of 248.98

Mariana [72]

Answer:

the answer is 16.1837

Step-by-step explain

5 0

2 years ago

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For nitrogen to be a liquid, its temperature must be within 12.78 °F of –333.22 °F. Which equation can be used to find the maxim

ziro4ka [17]

To determine the maximum and minimum temperatures at which nitrogen remains a liquid, use the equation |x - (-333.32)| = 12.78, where x is equal to the maximum and minimum temperatures. Using this equation, the maximum temperature is -320.54 degrees Fahrenheit while the minimum is -346.10 degrees Fahrenheit.

3 0

2 years ago

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What is the area of the figure?

Pie

Answer:

80.2

Step-by-step explanation:

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1 year ago