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Lynna [10]
3 years ago
7

santosh is four more than three times the age of his cousin. if santosh is 49 years old, then what is the age of his cousin?

Mathematics
1 answer:
andrezito [222]3 years ago
8 0
Santosh's cousin is 15 years old because 49-4=45. Divide 45 by 3 and the quotient is 15. To check: 15 times 3= 45. Add 4 and the sum is 49.
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What the answer for tje pythagorean
Aleks04 [339]
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7 0
3 years ago
Solve for X<br><br> PLEASE HELP ME
guapka [62]

Answer:

x = 10°

Step-by-step explanation:

Step 1:

92° + x° + 78° = 180°             Supplementary Angles

Step 2:

x° + 170° = 180°         Combine Like Terms

Step 3:

x° = 180° - 170°       Subtract 170° on both sides

Answer:

x = 10°

Hope This Helps :)

4 0
3 years ago
elise is changing the dimensions of her garden. the length is 20 feet longer than its width. if she decreases this length by 8 f
vitfil [10]
Let x be the initial width, then the initial length is x+20.
<span>If Elise decreases this length by 8 feet, she will get the new length  x+20-8=x+12.
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 If Elise increases the width by 10 feet, <span>she will get the new width x+10.
</span><span>
</span><span>The new perimeter will be x+12+x+12+x+10+x+10=4x+44=172, 4x=172-44, 4x=128,  x=128÷4, x=32.
</span><span>
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</span><span>
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4 0
3 years ago
What are the roots to<br> the equation<br> 2x² + 6x-1=0?
lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = \frac{ - b}{a}

And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 (\frac{ - 1}{2})

Or, (m - n)² = 9 + 2 = 11

I.e m - n = \sqrt{11}

Again m + n = - 3    And m - n = \sqrt{11}

Solving this two equation

(m + n) + ( m - n) = - 3 + \sqrt{11}

I.e 2 m =  - 3 + \sqrt{11}

Or, m = \frac{-3}{2} + \frac{\sqrt{11} }{2}

Similarly n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      

Hence the roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      Answer

6 0
3 years ago
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